Countdown timer for Lua script

0
votes

I am completely new to the Lua programming language, I've only been working with it a few days in total. Although, I do have some experience in Python, C# and Ada.

I am currently trying to make a racing game, one of the aspects of the game I'm trying to include is a countdown timer that ends the game after 90 seconds, then returning to a high score screen, regardless of whether or not the player has eliminated all of their lives already. I haven't a clue what functions to include nor where the place the text in the main script. Some advice would be much appreciated.

2
luacoronasdkcountdown

2 Answers

1
votes

When the game starts do:

local startTime = os.time()
local endTime = startTime+90

Then regularely do:

if os.time() >= endTime then
    -- exit game
    -- return to high score screen
end

until the game ends. Probably this would be in a callback function that gets called regularely. Depending on how your framework works, a loop might also work.

1
votes

Use timer.performWithDelay to call a specified function after a delay.

Example

local function countdown( event )
    print( "listener called" )
end

timer.performWithDelay( 1000, countdown, 90 )