So I have tried around a bit since this sounded interesting and I am currently learning python.
Please find the following code.
This works with your samples.
However if you have a bigger hole of subsequent keys in the master file, it mixes up the order. I was not able to fix it.
I really had a lot of issues with the data structure having duplicate primary keys distributed over several rows.
I dont know what you are doing exactly, but I am working a lot with databases and I can tell you, that this kind of data structure is highly unusual. You would probably benefit a lot if you would restructe your data set.
with this amount of data you would probably benefit from storing it in a database. If you are not running deep learning algos over it.
Example:
this is the example where it mixes up the order, but works nontheless
Master file
Key1|AAA|BBB|CCC
Key1|AAA|BBB|DDD
Key1|XXX|YYY|ZZZ
Key2|ZZZ|YYY|123
Key2|EEE|FFF|RRR
Key3|RRR|EEE|GGG
Key3|SSS|TTT|GGG
Key7|RRR|EEE|GGG
Key7|SSS|TTT|GGG
changefile
Key1|111|222|333
Key1|222|333|444
Key1|222|333|555
Key4|888|333|222
Key4|888|777|222
Key5|888|333|222
Key5|888|777|222
Key6|888|333|222
Key6|888|777|222
Key8|888|333|222
Key8|888|777|222
Key9|888|333|222
Key9|888|777|222
Code:
import fileinput
with open('changefile.txt') as infile:
keyindex = []
for line in infile:
linelist = line.strip().split("|") ## split line by |
key = linelist[0] ## assign the key
keyid = linelist[0][3:] ## assign keyid
keylist = [] ## assign keylist for loop
## finding duplicate keys in changefile and assign them to list
if key not in keyindex: ## we need this because multiple keys in multiple lines
with open('changefile.txt') as infile2:
#spawning extra loop for each new key to open and search all duplicate keys and assign them to list
for line2 in infile2:
if line2.startswith(key):
print(line2)
keylist.append(line2)
## Delete line with current key of loop from master file
keyindex.append(key)
print(keylist)
for linem in fileinput.input('test.txt', inplace=True):
if key in linem:
continue
print(linem, end='')
## insert keys from keyindex
for linei in fileinput.input('test.txt', inplace=1):
if 'Key'+str(int(keyid)+1) in linei: ## This statement is case sensitive
for item in keylist:
print(item, end='')
keylist = []
print(linei, end='')
# I had problems with not beeing able to go to next line at the beginning of this code if you fix this, this would be better then opening the file anew
## if last in linei and keylist:
## ##print('\n')
## for item in keylist:
## print(item, end='')
## keylist = []
## print('\n')
## this block may cause problem with memory you may can fix this with the comment block before this.
## this block is for adding left over keys from the end of change file to the end of master e.g. id 9 is in changefile, but masterfile is only going to key8
with open("test.txt", "a") as myfile:
if keylist:
for item in keylist:
myfile.write(item)
keylist = []
else:
continue
## because we spawned a seperate loop each time we find a new key, we can skip the duplicate lines
else:
## print('>>>key '+line+'already worked at! go to next line') # if you want to skip, uncomment continue and comment this
continue
##print all keyindexes that have been changed
print('Following keys have been changed:'keyindex)