make changes to nodes between other sibling nodes in XSLT

Question

I am a beginner to xslt and would very much appreciate your help for the below-mentioned issue. Inside node <case>, I want to select <s> nodes between its first <beginning> and first <end> sibling nodes , the second <beginning> and the second <end> and respectively the n^th beginning and the n^th node; and add the attribute @attribute:unsolved to them. Meanwhile, I want to keep the rest of the xml file intact. My input and desired output are shown below. Thanks a lot for your help.

XML INPUT:

<content>
    <issue>1</issue>
    <status>to be solved</status>
</content> 
<case>
    <beginning>problem</beginning>
    <s>this</s>
    <s>is</s>
    <s>a</s>
    <s>problem</s>
    <end>problem</end>
    <s>no</s>
    <s>problem</s>
    <s>here</s>
    <s>.</s>
    <beginning>problem</beginning>
    <s>problem</s>
    <s>again</s>
    <end>problem</end>
    <s>no</s>
    <s>issue</s>
</case>

Desired output:

<content>
    <issue>1</issue>
    <status>to be solved</status>
</content>
<case>
    <beginning>problem</beginning>
    <s attribute='unsolved'>this</s>
    <s attribute='unsolved'>is</s>
    <s attribute='unsolved'>a</s>
    <s attribute='unsolved'>problem</s>
    <end>problem</end>
    <s>no</s>
    <s>problem</s>
    <s>here</s>
    <s>.</s>
    <beginning>problem</beginning>
    <s attribute='unsolved'>problem</s>
    <s attribute='unsolved'>again</s>
    <end>problem</end>
    <s>no</s>
    <s>issue</s>
</case>

Can you share the code what you have tried. What programming language are you using to achieve this? — Hussain Patel
I'm trying to write an XSLT stylesheet for this transformation from one XML file to another XML file. — Lena S
Assuming you can use XSLT 2.0 or 3.0 look at any example using xsl:for-each-group group-starting-with="beginning", the spec has w3.org/TR/xslt-30/#grouping-examples. — Martin Honnen
no! I just want to add the attribute unsolved to the nodes which are between <beginning> and <end> nodes. The rest of <s> nodes remain unchanged. — Lena S

Shok9894 Shok9894 · Accepted Answer · 2017-09-22T13:00:25

If I understand what you mean, then your XPath will be show like:

`//beginning/following::s[./following::end]
[
count(.|//end/following::s[./following::beginning])
!=
count(//end/following::s[./following::beginning])
]`

make changes to nodes between other sibling nodes in XSLT

1 Answers