Wolfram Alpha Solution Entry

Question

Using this Wolfram Alpha code either through web or in Mathematica:

(5y^4+3y^2+e^y)y'=cos(x),y(0)=0

My equation seems to be properly parsed:

{(5 y(x)^4 + 3 y(x)^2 + e^(y(x))) y'(x) = cos(x), y(0) = 0}

As a separable DE, the result should be:

y^5 + y^3 + e^y = sin(x) + 1

How do I modify the original Wolfram Alpha code to get the program to evaluate the solution?

Answer 1

Using Wolfram Alpha

{(5y[x]^4+3y[x]^2+E^y[x])y'[x]==Cos[x],y[0]==0} solution