What does this jcl code do?

Question

//ACTUPT EXEC PGM=finance.ACCTREC.UPDATE, REGION=1M,TIME=(,6),COND= (0,EQ, 
VALIDATE)

I understand this code allocates 1M of memory, the processor can take up to 45 seconds and that to make sure the return code equals zero. I do not understand "//ACTUPT" or "PGM=finance.ACCTREC.UPDATE". I think that what appears after PGM is the account name then the step name and the DDName but I would like to verify.

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cschneid cschneid · Accepted Answer · 2017-06-23T19:25:34

This JCL contains a number of syntax errors, so it will simply result in a JCL error as written.

REGION= does not allocate memory, it limits the amount of memory that can be allocated. 1M is a ridiculously small region these days.

TIME= will limit the step to 6 seconds of CPU.

As it is coded, COND= will only execute this step if the condition code from the step named VALIDATE is not zero.

ACTUPT is the step name, the preceding // is syntactically required by JCL.

PGM=finance.ACCTREC.UPDATE is a syntax error, if it were written as PGM=*.FINANCE.ACCTREC.UPDATE it would indicate to execute the program in the temporary library named by the DDNAME UPDATE in the ACCTREC procstep and the step FINANCE. Perhaps I led a sheltered career, but I've never before seen a PGM= parameter written this way.

Cleaning up syntax errors, I suspect we get...

//ACTUPT EXEC PGM=*.FINANCE.ACCTREC.UPDATE,
//          REGION=1M,TIME=(,6),COND=(0,EQ,VALIDATE)

I strongly suggest you familiarize yourself with the IBM Documentation. JCL is under z/OS MVS in the table of contents.

What does this jcl code do?

1 Answers