Is it possible to query table and show certain columns without looping of all the results?
So, I have this query
$shipping = Preferences::where('preferences_id', '=', 1)->get();
Now I'm trying to get this columns
$shipping->option_one
$shipping->option_two
The error is obviously
Undefined property: Illuminate\Database\Eloquent\Collection::$preferences_option_one
Undefined property: Illuminate\Database\Eloquent\Collection::$preferences_option_two
How can I do this?
print_r($shipping)
Array
(
[0] => stdClass Object
(
[preferences_id] => 1
[preferences_option_one] => Priority Mail
[preferences_option_two] => Express Mail
)
)
1
Error:
[2017-05-30 10:06:10] production.ERROR: Symfony\Component\Debug\Exception\FatalErrorException: Uncaught TypeError: Argument 1 passed to Illuminate\Exception\WhoopsDisplayer::display() must be an instance of Exception, instance of TypeError given, called in /var/www/html/vendor/laravel/framework/src/Illuminate/Exception/Handler.php on line 281 and defined in /var/www/html/vendor/laravel/framework/src/Illuminate/Exception/WhoopsDisplayer.php:43
/var/www/html/vendor/laravel/framework/src/Illuminate/Exception/Handler.php line 281
protected function displayException($exception)
{
$displayer = $this->debug ? $this->debugDisplayer : $this->plainDisplayer;
return $displayer->display($exception); <--- line 281
}
/var/www/html/vendor/laravel/framework/src/Illuminate/Exception/WhoopsDisplayer.php:43
public function display(Exception $exception) <-- line 43
{
$status = $exception instanceof HttpExceptionInterface ? $exception->getStatusCode() : 500;
$headers = $exception instanceof HttpExceptionInterface ? $exception->getHeaders() : array();
return new Response($this->whoops->handleException($exception), $status, $headers);
}