Opening an Image from a specific file?

Question

import glob
import numpy as np
from PIL import Image

filename = glob.glob('/home/ns3/PycharmProjects/untitled1/stego.pgm')
im= Image.open(filename)
(x,y) = im.size
I = np.array(im.getdata()).reshape(y, x)

Keeps giving me this error:

im= Image.open(filename)

File "/home/ns3/.local/lib/python2.7/site-packages/PIL/Image.py", line 2416, in open fp = io.BytesIO(fp.read())

AttributeError: 'list' object has no attribute 'read

How can I open an image from that specific path and use the image as array I?

Reread the documentation: glob.glob() returns a list of names that match the pattern. Why are you using glob() to access a specific file? Why not filename = '/home/ns3/PycharmProjects/untitled1/stego.pgm'? — Warren Weckesser
so how can I read that image from the specified path @WarrenWeckesser ? — Charles B
filename = '/home/ns3/PycharmProjects/untitled1/stego.pgm' should work. — Warren Weckesser

Merlin Katz Merlin Katz · Accepted Answer · 2017-05-05T17:10:57

The issue is that glob.glob() returns a list (a possibly-empty list of path names that match pathname) and you want a string.

so either insert a [0]

import glob
import numpy as np
from PIL import Image

filenames = glob.glob('/home/ns3/PycharmProjects/untitled1/stego.pgm')
filename = filenames[0]
im= Image.open(filename)
(x,y) = im.size
I = np.array(im.getdata()).reshape(y, x)

or skip glob all together

import numpy as np
from PIL import Image

filename = '/home/ns3/PycharmProjects/untitled1/stego.pgm'
im= Image.open(filename)
(x,y) = im.size
I = np.array(im.getdata()).reshape(y, x)

Opening an Image from a specific file?

1 Answers