My data looks like this:
I am trying to make it look like this:
I would like to do this in tidyverse using %>%-chaining.
df <-
structure(list(id = c(2L, 2L, 4L, 5L, 5L, 5L, 5L), start_end = structure(c(2L,
1L, 2L, 2L, 1L, 2L, 1L), .Label = c("end", "start"), class = "factor"),
date = structure(c(6L, 7L, 3L, 8L, 9L, 10L, 11L), .Label = c("1979-01-03",
"1979-06-21", "1979-07-18", "1989-09-12", "1991-01-04", "1994-05-01",
"1996-11-04", "2005-02-01", "2009-09-17", "2010-10-01", "2012-10-06"
), class = "factor")), .Names = c("id", "start_end", "date"
), row.names = c(3L, 4L, 7L, 8L, 9L, 10L, 11L), class = "data.frame")
What I have tried:
data.table::dcast( df, formula = id ~ start_end, value.var = "date", drop = FALSE ) # does not work because it summarises the data
tidyr::spread( df, start_end, date ) # does not work because of duplicate values
df$id2 <- 1:nrow(df)
tidyr::spread( df, start_end, date ) # does not work because the dataset now has too many rows.
These questions do not answer my question:
Using spread with duplicate identifiers for rows (because they summarise)
R: spread function on data frame with duplicates (because they paste the values together)
Reshaping data in R with "login" "logout" times (because not specifically asking for/answered using tidyverse and chaining)
as.data.table(df)[, .id := sequence(.N), .(id, start_end)][, dcast(.SD, .id + id ~ start_end, value.var = "date")]
? – A5C1D2H2I1M1N2O1R2T1reshape2
anddplyr
:df %>% group_by(id, start_end) %>% arrange(date) %>% mutate(sequence=1:n()) %>% dcast(id + sequence ~ start_end, value="date")
. – eipi10