How to use file parameter in jenkins

21
votes

I am executing parameterised build in jenkins to count no. of lines in file which has 1 file parameter. Its file location is pqr. The name of the script file is linecount.sh which is saved at remote server. When i tried to execute it using command sh linecount.sh filename, it works perfectly from jenkins. But as i remove filename from the argument and execute same script as parameterised build it is showing below error on console :

Started by user Prasoon Gupta
[EnvInject] - Loading node environment variables.
Building in workspace users/Prasoon/sample_programs
Copying file to pqr
[sample_programs] $ /bin/sh -xe /tmp/hudson3529902665956638862.sh
+ sh linecount.sh
PRASOON4
linecount.sh: line 15: parameterBuild.txt: No such file or directory
Build step 'Execute shell' marked build as failure
Finished: FAILURE

I am uploading file (parameterBuild.txt) from my local machine. Why is it giving this error?

My doubt is in shell script I used argument as $1. How can I refer this when I am taking file as parameter.

4
jenkins
Make sure that the parameter file is inserted as you expect into the workspace, e.g. do a ls -l in your shell command. – Jon S
Thank you but i want to upload it directly from my local machine, want to make my job more user friendly. – Prasoon Gupta
Yes, understand that. But in order to isolate the issue, what happens if you run ls -l as part of your shell command in the job configuration? E.g. does it list parameterBuild.txt there or any other files? – Jon S
No, it doesn't lists parameterBuild.txt there but a new file named same as logical name of my file location (here pqr) is created there having all the content as in parameterBuild.txt. – Prasoon Gupta
Ah, I see, my bad, misread some of your question. I've posted an answer. – Jon S

4 Answers

31
votes

The uploaded file will not retain the same name as it has on your local computer. It will be named after the File location argument specified in the file parameter settings: enter image description here In this example I will get a file called file.txt in my workspace root, regardless of what I call it on my computer. So if I now build my job and enter the following in the parameter dialog (note that my local filename is table.html):

enter image description here

Then I get the following in the log (I have a build step which does ls -l):

Building on master in workspace /var/lib/jenkins/workspace/fs
Copying file to file.txt
[fs] $ /bin/sh -xe /tmp/hudson845437350739055843.sh
+ ls -l
total 4
-rw-r--r-- 1 jenkins jenkins 292 Feb 15 07:23 file.txt
Finished: SUCCESS

Note that table.html now is called file.txt, e.g. what I entered as File location.

So in you're case the command should be:

sh linecount.sh pqr
2
votes

There is a a bug since ages that makes impossible to use fileParameter:

2
votes

There is a workaround for this issue https://github.com/janvrany/jenkinsci-unstashParam-library and in a pipeline script you do:

library "jenkinsci-unstashParam-library"
node {
  def file_in_workspace = unstashParam "file"
  sh "cat ${file_in_workspace}"
}
0
votes

If it's to do with Free-Style job & if your configuration looks similar to this - https://i.stack.imgur.com/vH7mQ.png then you can run simply do sh linecount.sh ${pqr} to get what you are looking for?