Extract zip contents into directory with same name as zip file, retain directory structure [closed]

Question

I would like to write a bat script to do the following:

Use 7 Zip to extract files from an existing zip file, into a folder by the same name as the original zip file (bar the .zip extension), and keeping the file & directory structure that was contained in the zip file.

I can extract all the same files into the current directory, by using

"C:\Program Files (x86)\7-Zip\7z.exe" e  myZipFile.zip

@Harriet On using 7-Zip from command line it is always advisable to open help of 7-Zip - the file 7-zip.chm in program files folder of 7-Zip - and read in help on tab Contents the pages listed under list item Command Line Version. The commands e and x are both explained in help as well as all other commands and switches. You would have just needed to read the help. — Mofi

geisterfurz007 geisterfurz007 · Accepted Answer · 2017-01-30T10:06:14

Reading the help of the 7z-command by just typing "C:\Path To\7-Zip\7z.exe" gets the help with all possible arguments. Here we find the following interesting ones:

 e : Extract files from archive (without using directory names)

and

x : eXtract files with full paths

Trial and error shows that the latter is the one fitting your desired behaviour without bigger effort :)

After the comment by @BadmintonCat here is the addition that will create a folder to zip everything into (use as batch script with the file as argument):

@echo off

SET "filename=%~1"
SET dirName=%filename:~0,-4%

7z x -o"%dirName%" "%filename%"

From the help: -o{Directory} : set Output directory. 7z will create the directory if it does not already exist.

Extract zip contents into directory with same name as zip file, retain directory structure [closed]

2 Answers