3
votes

I'm using Spring(xml+annotations), Hibernate(annotations) in this web service project. The database relationship diagram, models, expected and actual output are given below,

Database Table relationship

Customer.java

@Entity
@Table(name="customer")
public class Customer implements Serializable{
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name="customer_id", unique=true, nullable =false)
    long customerId;
    @Column(name="name")
    String name;
    @Column(name="secondary_name")
    String secondaryName;
    @Column(name="date")
    Date date;
    @Column(name="address")
    String address;
    @Column(name="post")
    String post;
    @Column(name="pin")
    String pin;
    @Column(name="phone")
    String phone;
    @OneToMany(fetch=FetchType.LAZY, mappedBy="customer", cascade=CascadeType.ALL)
    @JsonManagedReference
    Set<Loan> loans = new HashSet<Loan>();
    //constructors, getters and setters
}

Loan.java

public class Loan implements Serializable{
    /**
     * 
     */
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name="loan_id", nullable=false, unique=true)
    long loanId;
    @ManyToOne(fetch = FetchType.EAGER, cascade=CascadeType.ALL)
    @JoinColumn(name="customer_id", nullable = false)
    @JsonBackReference
    Customer customer;
    @Column(name="date", nullable=false)
    Date date;
    @Column(name="amount", nullable=false)
    double amount;
    @OneToMany(fetch=FetchType.LAZY, mappedBy="loan", cascade=CascadeType.ALL)
    @JsonManagedReference
    List<Item> items = new ArrayList<Item>();
    //constructors, getters, setters
}

Item.java

public class Item implements Serializable{
    /**
     * 
     */
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name="item_id", nullable=false, unique=true)
    long itemId;
    @ManyToOne(fetch=FetchType.LAZY, cascade=CascadeType.ALL)
    @JoinColumn(name="loan_id", nullable = false)
    @JsonBackReference
    Loan loan;
    @Column(name="name", nullable=false)
    String name;
    @Column(name="weight", nullable=false)
    double weight;
    //constructors, setters, getters
}

Actual output:Here, customer details are not shown

{  
   "loanId":4,
   "date":1484937000000,
   "amount":10000.0,
   "items":[  
      {  
         "itemId":3,
         "name":"Item1",
         "weight":10.0
      },
      {  
         "itemId":4,
         "name":"Item2",
         "weight":20.0
      }
   ]
}

Expected output: need to display customer details also when looking for a loan

{  
   "loanId":4,
   "customer":{  
      "customerId":2,
      "name":"Prem",
      "address":"Street,State"
   },
   "date":1484937000000,
   "amount":10000.0,
   "items":[  
      {  
         "itemId":3,
         "name":"Item1",
         "weight":10.0
      },
      {  
         "itemId":4,
         "name":"Item2",
         "weight":20.0
      }
   ]
}

I can able to fetch the customer details from the database and fail to load it using Jackson Json. If I remove @JsonManagedReference, I end up with circular loop. If I remove @JsonBackReference, no effects in the output. Complete code at: https://github.com/liwevire/TM_Service Thanks in advance.

3

3 Answers

16
votes

Because you are using the @JsonBackReference on the Customer property in the Loan entity, the Customer object will not included in the serialization. Use the @JsonManagedReference for the Customer in the Loan object and use @JsonBackReference on the Loan property in the Customer entity.

This will serialize the Customer property of your Loan entity. But the Customer object serialization will not contains the Loan property. You need to pick one side of the relationship to serialize.

To allow both side, use @JsonIdentityInfo annotation in your entity and remove the @JsonBackReference and @JsonManagedReference. You entities will be something like:

@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "customerId")
public class Customer implements Serializable {
    ...
}

The property of the @JsonIdentityInfo refer to your entity id property, for Customer this will be customerId. Do this for Loan and Item also.

1
votes

This seems pretty old but let me put my coins here as well; I would seperate the entity and model. Means;

> Client <-> Application : Models
> 
> Application <-> Database : Entities

And your service layer or whatever layer you process data should make the conversion between entities and models.

  1. You get rid of recursion by returning data as your wish.
  2. You split the definitions between two different communication channels. This way you can decide what to show to your client and how to show your client as well. This will save your DB schema be exposed directly too.
  3. You can extend model as per your wish without touching to the DB backend.
1
votes

Here is a bit lengthy approach. But needs some design modifications in your app. I had a similar problem and I created separate pojos for every entity classes.

In service layer I use these pojos instead of the entity objects as parameters and I use appropriate getters/setters to set/get the properties to/from entity classes. In this way you can get/set the properties you want to and avoid unwanted ones. However I implemented additional methods in DAO layer to get the related entities. This is very lengthy approach but solved the problem for me.