Get Get-WmiObject -Class Win32_Product Output on GUI Form

0
votes

Hi I'm new to Powershell. I'm looking Get-WmiObject -Class Win32_Product output on a GUI Form. Thanks in Advance.

Below is the Code, I need to add label to the buttons and assign a function to each button.

Label: Uninstall Function: Uninstall Start-Process Powershell -verb runas # Load Windows Forms assembly [void][System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms") [void][System.Windows.Forms.Application]::EnableVisualStyles() # Create a GUI $form = New-Object System.Windows.Forms.Form $form.Size = New-Object System.Drawing.Size(920,500) $form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::Fixed3D $form.StartPosition = [System.Windows.Forms.FormStartPosition]::CenterScreen $dataGridView = New-Object System.Windows.Forms.DataGridView $dataGridView.Size = New-Object System.Drawing.Size(900,400) $button = New-Object System.Windows.Forms.Button $button.Location = New-Object System.Drawing.Size(400,420) $button.Size = New-Object System.Drawing.Size(75,25) $button.text = "Uninstall" $form.Controls.Add($button) $form.Controls.Add($dataGridView) # Select appropriate columns $dataGridView.Columns.Insert(0, (New-Object System.Windows.Forms.DataGridViewButtonCell)) $dataGridView.ColumnCount = 8 $dataGridView.ColumnHeadersVisible = $true $dataGridView.Columns[0].Name = "Uninstall" $dataGridView.Columns[1].Name = "Description" $dataGridView.Columns[2].Name = "IdentifyingNumber" $dataGridView.Columns[3].Name = "Name" $dataGridView.Columns[4].Name = "Vendor" $dataGridView.Columns[5].Name = "Version" $dataGridView.Columns[6].Name = "Caption" $dataGridView.Columns[7].Name = "InstallLocation" $dataGridView.Columns[0].width = 40 $dataGridView.Columns[1].width = 200 # Get a list of items <#Get-WmiObject -Class Win32_Product | foreach { $dataGridView.Rows.Add($.Check,$.Description,$.IdentifyingNumber,$.Name,$.Vendor,$.Version,$.Caption,$.InstallLocation) | out-null }#> # Refresh function gridClick(){ $rowIndex = $dataGridView.CurrentRow.Index $columnIndex0 = $dataGridView.ColumnIndex+1 $columnIndex1 = $dataGridView.ColumnIndex+2 $columnIndex2 = $dataGridView.ColumnIndex+3 $columnIndex3 = $dataGridView.ColumnIndex+4 $columnIndex5 = $dataGridView.ColumnIndex+5 #Write-Host $rowIndex #Write-Host $columnIndex0 #Write-Host $dataGridView.Rows[$rowIndex].Cells[0].value Write-Host $dataGridView.Rows[$rowIndex].Cells[$columnIndex0].value Write-Host $dataGridView.Rows[$rowIndex].Cells[$columnIndex1].value Write-Host $dataGridView.Rows[$rowIndex].Cells[$columnIndex5].value #$IdentifyNumber = $dataGridView.Rows[$rowIndex].Cells[$ClassKey].value #$Name = $dataGridView.Rows[$rowIndex].Cells[$columnIndex0].value #$classKey = 'IdentifyingNumber=$IdentifyingNumber.value,Name=$Name.value,Version=$Version.value' #Write-Host $classKey #([wmi]”\$server\root\cimv2:Win32_Product.$classKey”).uninstall() } $Uninstall = $dataGridView.Add_CellMouseClick({gridClick}) # Show the form [void]$form.ShowDialog()

2
powershellpowershell-2.0powershell-3.0powershell-4.0
Which Powershell version? Tagging specific version means that solution that worksi only on that version is desired. As PS2/3/4 are quite different, tagging all those might not be relevant. – vonPryz
What kind of GUI form are you looking for, anyway? Would Out-GridView be good enough? – vonPryz
Thanks for the reply.. Out-Gridview is fair for me but Matt Szadziul ans is what i'm looking for. – Deep

2 Answers

3
votes

You can use this method to see a GUI grid :

gwmi -Class win32_product | Out-GridView

and also you can get custom output like XML and CSV and json and other form and use special software for that .

1
votes

This might be a bit of an overkill but you can always create a customized GUI form and paint the output in a gridview control like this:

# Load Windows Forms assembly

[void][System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms") 
[void][System.Windows.Forms.Application]::EnableVisualStyles()

# Create a GUI

$form = New-Object System.Windows.Forms.Form
$form.Size = New-Object System.Drawing.Size(920,500)
$form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::Fixed3D
$form.StartPosition = [System.Windows.Forms.FormStartPosition]::CenterScreen
$dataGridView = New-Object System.Windows.Forms.DataGridView
$dataGridView.Size = New-Object System.Drawing.Size(900,400)
$button = New-Object System.Windows.Forms.Button
$button.Location = New-Object System.Drawing.Size(400,420)
$button.Size = New-Object System.Drawing.Size(75,25)
$button.Text = "Refresh"
$form.Controls.Add($button)
$form.Controls.Add($dataGridView)

# Select appropriate columns

$dataGridView.ColumnCount = 7
$dataGridView.ColumnHeadersVisible = $true
$dataGridView.Columns[0].Name = "Description"
$dataGridView.Columns[1].Name = "IdentifyingNumber"
$dataGridView.Columns[2].Name = "Name"
$dataGridView.Columns[3].Name = "Vendor"
$dataGridView.Columns[4].Name = "Version"
$dataGridView.Columns[5].Name = "Caption"
$dataGridView.Columns[6].Name = "InstallLocation"

$dataGridView.Columns[0].width = 240

# Get a list of items

Get-WmiObject -Class Win32_Product | foreach {
    $dataGridView.Rows.Add($_.Description,$_.IdentifyingNumber,$_.Name,$_.Vendor,$_.Version,$_.Caption,$_.InstallLocation) | out-null
}

# Refresh

$button.Add_Click({

    $dataGridView.Rows.Clear()

    start-sleep -s 1

Get-WmiObject -Class Win32_Product | foreach {
    $dataGridView.Rows.Add($_.Description,$_.IdentifyingNumber,$_.Name,$_.Vendor,$_.Version,$_.Caption,$_.InstallLocation) | out-null
}

})

# Add a cell click function

function cellClick(){
$rowIndex = $dataGridView.CurrentRow.Index
$columnIndex = $dataGridView.CurrentCell.ColumnIndex
$value = $dataGridView.Rows[$rowIndex].Cells[$columnIndex].value
write-host $value
}

$dataGridView.Add_CellMouseClick({cellClick})

# Show the form

[void]$form.ShowDialog()