How can I convert hex color to RGB code in Java? Mostly in Google, samples are on how to convert from RGB to hex.
109
votes
19 Answers
173
votes
40
votes
10
votes
Here is a version that handles both RGB and RGBA versions:
/**
* Converts a hex string to a color. If it can't be converted null is returned.
* @param hex (i.e. #CCCCCCFF or CCCCCC)
* @return Color
*/
public static Color HexToColor(String hex)
{
hex = hex.replace("#", "");
switch (hex.length()) {
case 6:
return new Color(
Integer.valueOf(hex.substring(0, 2), 16),
Integer.valueOf(hex.substring(2, 4), 16),
Integer.valueOf(hex.substring(4, 6), 16));
case 8:
return new Color(
Integer.valueOf(hex.substring(0, 2), 16),
Integer.valueOf(hex.substring(2, 4), 16),
Integer.valueOf(hex.substring(4, 6), 16),
Integer.valueOf(hex.substring(6, 8), 16));
}
return null;
}
5
votes
4
votes
A hex color code is #RRGGBB
RR, GG, BB are hex values ranging from 0-255
Let's call RR XY where X and Y are hex character 0-9A-F, A=10, F=15
The decimal value is X*16+Y
If RR = B7, the decimal for B is 11, so value is 11*16 + 7 = 183
public int[] getRGB(String rgb){
int[] ret = new int[3];
for(int i=0; i<3; i++){
ret[i] = hexToInt(rgb.charAt(i*2), rgb.charAt(i*2+1));
}
return ret;
}
public int hexToInt(char a, char b){
int x = a < 65 ? a-48 : a-55;
int y = b < 65 ? b-48 : b-55;
return x*16+y;
}
1
votes
1
votes
1
votes
For Android Kotlin developers:
"#FFF".longARGB()?.let{ Color.parceColor(it) }
"#FFFF".longARGB()?.let{ Color.parceColor(it) }
fun String?.longARGB(): String? {
if (this == null || !startsWith("#")) return null
// #RRGGBB or #AARRGGBB
if (length == 7 || length == 9) return this
// #RGB or #ARGB
if (length in 4..5) {
val rgb = "#${this[1]}${this[1]}${this[2]}${this[2]}${this[3]}${this[3]}"
if (length == 5) {
return "$rgb${this[4]}${this[4]}"
}
return rgb
}
return null
}
0
votes
To elaborate on the answer @xhh provided, you can append the red, green, and blue to format your string as "rgb(0,0,0)" before returning it.
/**
*
* @param colorStr e.g. "#FFFFFF"
* @return String - formatted "rgb(0,0,0)"
*/
public static String hex2Rgb(String colorStr) {
Color c = new Color(
Integer.valueOf(hexString.substring(1, 3), 16),
Integer.valueOf(hexString.substring(3, 5), 16),
Integer.valueOf(hexString.substring(5, 7), 16));
StringBuffer sb = new StringBuffer();
sb.append("rgb(");
sb.append(c.getRed());
sb.append(",");
sb.append(c.getGreen());
sb.append(",");
sb.append(c.getBlue());
sb.append(")");
return sb.toString();
}
0
votes
0
votes
Here is another faster version that handles RGBA versions:
public static int hexToIntColor(String hex){
int Alpha = Integer.valueOf(hex.substring(0, 2), 16);
int Red = Integer.valueOf(hex.substring(2, 4), 16);
int Green = Integer.valueOf(hex.substring(4, 6), 16);
int Blue = Integer.valueOf(hex.substring(6, 8), 16);
Alpha = (Alpha << 24) & 0xFF000000;
Red = (Red << 16) & 0x00FF0000;
Green = (Green << 8) & 0x0000FF00;
Blue = Blue & 0x000000FF;
return Alpha | Red | Green | Blue;
}
0
votes
0
votes
public static Color hex2Rgb(String colorStr) {
try {
// Create the color
return new Color(
// Using Integer.parseInt() with a radix of 16
// on string elements of 2 characters. Example: "FF 05 E5"
Integer.parseInt(colorStr.substring(0, 2), 16),
Integer.parseInt(colorStr.substring(2, 4), 16),
Integer.parseInt(colorStr.substring(4, 6), 16));
} catch (StringIndexOutOfBoundsException e){
// If a string with a length smaller than 6 is inputted
return new Color(0,0,0);
}
}
public static String rgbToHex(Color color) {
// Integer.toHexString(), built in Java method Use this to add a second 0 if the
// .Get the different RGB values and convert them. output will only be one character.
return Integer.toHexString(color.getRed()).toUpperCase() + (color.getRed() < 16 ? 0 : "") + // Add String
Integer.toHexString(color.getGreen()).toUpperCase() + (color.getGreen() < 16 ? 0 : "") +
Integer.toHexString(color.getBlue()).toUpperCase() + (color.getBlue() < 16 ? 0 : "");
}
I think that this wil work.
-1
votes
The other day I'd been solving the similar issue and found convenient to convert hex color string to int array [alpha, r, g, b]:
/**
* Hex color string to int[] array converter
*
* @param hexARGB should be color hex string: #AARRGGBB or #RRGGBB
* @return int[] array: [alpha, r, g, b]
* @throws IllegalArgumentException
*/
public static int[] hexStringToARGB(String hexARGB) throws IllegalArgumentException {
if (!hexARGB.startsWith("#") || !(hexARGB.length() == 7 || hexARGB.length() == 9)) {
throw new IllegalArgumentException("Hex color string is incorrect!");
}
int[] intARGB = new int[4];
if (hexARGB.length() == 9) {
intARGB[0] = Integer.valueOf(hexARGB.substring(1, 3), 16); // alpha
intARGB[1] = Integer.valueOf(hexARGB.substring(3, 5), 16); // red
intARGB[2] = Integer.valueOf(hexARGB.substring(5, 7), 16); // green
intARGB[3] = Integer.valueOf(hexARGB.substring(7), 16); // blue
} else hexStringToARGB("#FF" + hexARGB.substring(1));
return intARGB;
}
-1
votes
For shortened hex code like #fff or #000
int red = "colorString".charAt(1) == '0' ? 0 :
"colorString".charAt(1) == 'f' ? 255 : 228;
int green =
"colorString".charAt(2) == '0' ? 0 : "colorString".charAt(2) == 'f' ?
255 : 228;
int blue = "colorString".charAt(3) == '0' ? 0 :
"colorString".charAt(3) == 'f' ? 255 : 228;
Color.rgb(red, green,blue);