Python error calculating

0
votes

I am having a problem with my code here. The error that I am receiving is on the bottom. I have to enter payroll in and calculate pay with overtime or without.

enter code here ####################### Functions ######################## def Input(): try: name=raw_input("Enter your first and last name: ") titlename=name.title() except: return Input

def Hours(): try: wHours=raw_input("Enter the hours you worked this week: ") except: if wHours < 1 or wHours > 60: print "Employees' can't work less than 1 hour or more than 60 hours." return lstEmp

def Pay(): try: pRate=raw_input("Enter your hourly wage: ") except: if pRate < 6 or pRate > 20: print "Employees' wages can't be lower than $6.00 or greater than $20.00." return pay

def calcHours(pr,h): if h <= 40: pr * h else: (h -40) *(pr *1.5) + pr * 40 return lstEmp

def end(): empDone=raw_input("Please type DONE when you are finished with employees' information: ") empDone.upper() == "DONE"

#################### MAINLINE CODE

lstEmp=[] Names=""

while True: Names=Input()

WorkHours=Hours()
Wages=Pay()
gPay=calcHours(WorkHours, Wages)

Done=end()
if end():
    break

Traceback (most recent call last): File "J:\11-2-10.py", line 53, in gPay=calcHours(WorkHours, Wages) File "J:\11-2-10.py", line 29, in calcHours pr * h TypeError: unsupported operand type(s) for *: 'NoneType' and 'NoneType'

2
python
try/except doesn't do what you think it does. You probably want to use if instead. You also need to be consistent with your variable names Pay, pRate, and pay look like they are supposed to be the same thing - John La Rooy
Yeah. There are quite a few errors here. - pyfunc
I am deleting my answer. You should edit but not change your question completely. My answer is now completely obsolete and it is not worth the effort at all. - pyfunc
sorry i am new to the forum thing - HENRY

2 Answers

0
votes

In Input, Hours and Pay, you assign to a variable of the same name as the functions; perhaps you mean to return these values instead?

0
votes
gPay=calcHours(Hours, Pay)

You meant WorkHours, which is what you called the variable; Hours is still the function, that returned it. There are plenty of other places in the code where you've changed the variable names so they don't match any more.

Also +1 gnibbler's comment. That's really not what try does, and you should never use except without a particular Exception. The bit you might want to put in the try is a conversion to integer:

def getHours():
    while True:
        hours= raw_input("Enter the hours you worked this week: ")
        try:
            hours= int(hours)
        except ValueError:
            print "That's not a number, type it proper."
            continue
        if not 1<=hours<=60:
            print "Employees must work between 1 and 60 hours."
            continue
        return hours