Haskell Couldn't match expected type ‘Double’ with actual type ‘Int’

0
votes

This is the code of my program:

funct :: Double -> Double
funct x = 3/(x^2+1)

zetaRange :: (Int, Int) -> [Double]
zetaRange (x,y) = [ 0.01 * funct n | n <- [x..y] ]

and error, which I'm getting:

Couldn't match expected type ‘Double’ with actual type ‘Int’

In the first argument of ‘funct’, namely ‘n’

In the second argument of ‘(*)’, namely ‘funct n’

I really newbie to haskell, so trying to fix this error wasn't successful. funct is returning Double, so I can't understand why error says that it's actual type is Int. Please, help!

1
haskell
Why is this tagged with "multithreading"? The question has nothing to do with multithreading. – Rein Henrichs
Wait. Aren't you the same user that asked two question about Haskell and concurrency? Your user name is eerily familiar… – Zeta
It says in the first argument of 'funct'. Not in the return type! – user253751

1 Answers

4
votes

You need to convert the Int n to a Double:

zetaRange (x,y) = [ 0.01 * funct (fromIntegral n) | n <- [x..y] ]