75
votes

this is my Python3 project hiearchy:

projet
  \
  script.py
  web
    \
    index.html

From script.py, I would like to run a http server which serve the content of the web folder.

Here is suggested this code to run a simple http server:

import http.server
import socketserver

PORT = 8000
Handler = http.server.SimpleHTTPRequestHandler
httpd = socketserver.TCPServer(("", PORT), Handler)
print("serving at port", PORT)
httpd.serve_forever()

but this actually serve project, not web. How can I specify the path of the folder I want to serve?

7
Have you considered running python3 -m http.server -d /path/to/web/dir on command line to do the job? Props to @kyle-barron who gave this perfect solution in a comment deep below. - Akseli Palén
I suggest this is the best answer: stackoverflow.com/a/58217918/835098 - Konrad Kleine
@AkseliPalén I get server.py: error: argument port: invalid int value: '/media/EHD/web_root' error when I run that in Ubuntu 18.04 Terminal (with python3.6.9) - Lost Crotchet

7 Answers

41
votes

https://docs.python.org/3/library/http.server.html#http.server.SimpleHTTPRequestHandler

This class serves files from the current directory and below, directly mapping the directory structure to HTTP requests.

So you just need to change the current directory prior to starting the server - see os.chdir

eg:

import http.server
import socketserver
import os

PORT = 8000

web_dir = os.path.join(os.path.dirname(__file__), 'web')
os.chdir(web_dir)

Handler = http.server.SimpleHTTPRequestHandler
httpd = socketserver.TCPServer(("", PORT), Handler)
print("serving at port", PORT)
httpd.serve_forever()
45
votes

If you just want serve static file you can do it by running SimpleHTTPServer module using python 2:

 python -m SimpleHTTPServer

Or with python 3:

 python3 -m http.server

This way you do not need to write any script.

44
votes

In Python 3.7 SimpleHTTPRequestHandler can take a directory argument:

import http.server
import socketserver

PORT = 8000
DIRECTORY = "web"


class Handler(http.server.SimpleHTTPRequestHandler):
    def __init__(self, *args, **kwargs):
        super().__init__(*args, directory=DIRECTORY, **kwargs)


with socketserver.TCPServer(("", PORT), Handler) as httpd:
    print("serving at port", PORT)
    httpd.serve_forever()

and from the command line:

python -m http.server --directory web

To get a little crazy... you could make handlers for arbitrary directories:

def handler_from(directory):
    def _init(self, *args, **kwargs):
        return http.server.SimpleHTTPRequestHandler.__init__(self, *args, directory=self.directory, **kwargs)
    return type(f'HandlerFrom<{directory}>',
                (http.server.SimpleHTTPRequestHandler,),
                {'__init__': _init, 'directory': directory})


with socketserver.TCPServer(("", PORT), handler_from("web")) as httpd:
    print("serving at port", PORT)
    httpd.serve_forever()
20
votes

Just for completeness, here's how you can setup the actual server classes to serve files from an arbitrary directory:

try
    # python 2
    from SimpleHTTPServer import SimpleHTTPRequestHandler
    from BaseHTTPServer import HTTPServer as BaseHTTPServer
except ImportError:
    # python 3
    from http.server import HTTPServer as BaseHTTPServer, SimpleHTTPRequestHandler


class HTTPHandler(SimpleHTTPRequestHandler):
    """This handler uses server.base_path instead of always using os.getcwd()"""
    def translate_path(self, path):
        path = SimpleHTTPRequestHandler.translate_path(self, path)
        relpath = os.path.relpath(path, os.getcwd())
        fullpath = os.path.join(self.server.base_path, relpath)
        return fullpath


class HTTPServer(BaseHTTPServer):
    """The main server, you pass in base_path which is the path you want to serve requests from"""
    def __init__(self, base_path, server_address, RequestHandlerClass=HTTPHandler):
        self.base_path = base_path
        BaseHTTPServer.__init__(self, server_address, RequestHandlerClass)

Then you can set any arbitrary path in your code:

web_dir = os.path.join(os.path.dirname(__file__), 'web')
httpd = HTTPServer(web_dir, ("", 8000))
httpd.serve_forever()
14
votes

There's a shorter method for Python 3+:

import functools
    
Handler = functools.partial(http.server.SimpleHTTPRequestHandler, directory='/my/dir/goes/here')
7
votes

You also can run the command line with

python3 -m http.server -d web 8000
0
votes

one small caveat. if you ran commands that fires up the server in another directory before, chances are your browser will remember it, and provide the previous webpage instead of the webpage you want now.

to get the currently specified webpage, do a hard refresh on your browser. that is ctrl + shift + r for firefox on ubuntu. but do look up your browser and your OS's keyboard shortcut for a hard refresh.