Why are parentheses needed on this F# function?

Question

Why are parentheses needed on read_rest_of_csv below?

    let read_rest_of_csv() =
        csv_data.Add(csv_fileH.ReadFields()) |> ignore
        not csv_fileH.EndOfData

    while read_rest_of_csv() do ignore None

Without the parentheses, the loop will not terminate.

open System
open System.Threading
open System.Collections.Generic
open System.Linq
open System.Text
open System.Threading.Tasks
open System.IO
open Microsoft.VisualBasic.FileIO

[<EntryPoint>]
let main argv =
    let csv_fileH = new TextFieldParser("test1.csv")
    csv_fileH.TextFieldType = FieldType.Delimited |> ignore
    let x = csv_fileH.SetDelimiters(",")
    let csv_data = new List<string[]>()

    let eod = csv_fileH.EndOfData
    if not eod then
        let column_headings = csv_fileH.ReadFields()
        csv_data.Add(column_headings) |> ignore

        let read_rest_of_csv =
            csv_data.Add(csv_fileH.ReadFields()) |> ignore
            not csv_fileH.EndOfData

        while read_rest_of_csv do ignore None

    0

I apologize that I cannot remember where I saw this. I think it was in SO. It's a nice example.

Could this be that without parens I'm dealing with a function object of sorts?

I am indeed coming from not only a C, C++, and C# background, but also an intermediate Clojure background as well. In my case with F# syntax, reading my Haskell manual in a little more detail might have helped, because the syntaxes seem similar.

Mark Seemann Mark Seemann · Accepted Answer · 2016-09-02T15:32:10

It seems that people coming from C-family languages (C#, Java, C, C++, JavaScript) are having problems understanding the use of brackets in F#. I certainly had, and it took me some years learning how things work.

In a nutshell, the most basic building block in F# is a value. Values can be let-bound:

let foo = bar

This means that foo is a value, which happens to be equal to bar.

Functions are also values:

// 'a -> 'a * 'a
let f = fun x -> x, x

Here, f is a function that takes some value (x) and returns a tuple with x as both the first and the second element.

That's a bit cumbersome to write, so there's a shorthand for that:

// 'a -> 'a * 'a
let f x = x, x

Notice that there are no brackets in these expressions.

Sometimes you need to adjust the precedence of operators. Just like in maths, 1 + 2 * 3 (which is equivalent to 1 + (2 * 3)) isn't the same as (1 + 2) * 3. In F#, you also use brackets to override precedence. Thus

// 'a -> string * 'a
let f x = someOtherFunction x, x

isn't the same as

// x:'a -> string
let f x = someOtherFunction (x, x)

(in this case, someOtherFunction is a function that returns a string.)

Notice that the brackets don't denote a function call; they're only there to control order of evaluation.

Sometimes, you want to define a function that doesn't take any input. You can't, however, define it like this:

let f = whatever

because that would make it a value that's immediately let-bound to whatever. Instead, you can let the function take a value of the built-in type unit. This type only has a single value, which is written ():

let f () = whatever

This means that f is a function that pattern matches its input against the only known value of unit.

Whenever you invoke f with (), the expression whatever is evaluated and returned.

Why are parentheses needed on this F# function?

3 Answers