Ok so I've been searching for a while and didn't get the answer. I imagine someone has this same problem but I was not able to solve this problem. I'm new to Lua, having some experience with Python but not being a programmer :S.
So I'm doing a metatable to handle complex numbers, following the tutorials here: http://www.dcc.ufrj.br/~fabiom/lua/
so I implement creation, addition, printing and equal comparison:
local mt={}
local function new(r,i)
return setmetatable({real = r or 0, im = i or 0},mt)
end
local function is_complex (v)
return getmetatable(v)==mt
end
local function add (c1,c2)
if not is_complex(c1) then
return new(c1+c2.real,c2.im)
end
if not is_complex(c2) then
return new(c1.real+c2,c1.im)
end
return new(c1.real + c2.real,c1.im + c2.im)
end
local function eq(c1,c2)
return (c1.real==c2.real) and (c1.im==c2.im)
end
local function modulus(c)
return (math.sqrt(c.real^2 + c.im^2))
end
local function tos(c)
return tostring(c.real).."+"..tostring(c.im).."i"
end
mt.new=new
mt.__add=add
mt.__tostring=tos
mt.__eq=eq
mt.__len=modulus
return mt
Then I make a small tests:
complex2=require "complex2"
print (complex2)
c1=complex2.new(3,2)
c2=complex2.new(3,4)
print (c1)
print (c2)
print(#{1,2})
print(#c2)
print(complex2.__len(c2))
print(#complex2.new(4,3))
and I get:
table: 0000000003EADBC0
3+2i
3+4i
2
0
5
0
So, What am I dong wrong? is something with calling the #, when i try to debug in the other cases the program goes to the module into the function but the # operand gets like ignored. Modulus function is working and can be called in the module... I'm sorry for such a long and I'm sure obvious question but I tried everything I could already. Thank you