In the following code, the scanf() in main() turns one of the input numbers from a non-zero number into zero, as shown by a debugging printf() in the while loop. I've tested it on several compilers but only to keep getting the same result. Please help me out by telling me why this is such. Thank you.
#include <stdio.h>
unsigned srl (unsigned x, int k)
{
/* perform shift arithmetically */
printf("x = %u, (int) x= %d\n", x, (int) x);
unsigned xsra = (int) x >> k;
printf("\nxsra before was: %u\n", xsra);
unsigned test = 0xffffffff;
test <<= ((sizeof (int) << 3) - k); // get e.g., 0xfff00...
printf("test after shift is: %x, xsra & test = %x\n", test, xsra & test);
if (xsra & test == 0) // if xsrl is positve
return xsra;
else
xsra ^= test; // turn 1s into 0s
return xsra;
}
int sra (int x, int k)
{
/* perform shift logically */
int xsrl = (unsigned) x >> k;
unsigned test = 0xffffffff;
test << ((sizeof (int) << 3) - k + 1); // get e.g., 0xffff00...
if (xsrl & test == 0) // if xsrl is positve
return xsrl;
else
xsrl |= test;
return xsrl;
}
int main(void)
{
int a;
unsigned b;
unsigned short n;
puts("Enter an integer and a positive integer (q or negative second number to quit): ");
while(scanf("%d%u", &a, &b) == 2 && b > 0)
{
printf("Enter the number of shifts (between 0 and %d): ", (sizeof (int) << 3) - 1);
scanf("%d", &n);
if (n < 0 || n >= ((sizeof (int)) << 3))
{
printf("The number of shifts should be between 0 and %d.\n", ((sizeof (int)) << 3) - 1);
break;
}
printf("\nBefore shifting, int a = %d, unsigned b = %u\n", a, b);
a = sra(a, n);
b = srl(b, n);
printf("\nAfter shifting, int a = %d, unsigned b = %u\n", a, b);
puts("\nEnter an integer and a positive integer (q or negative second number to quit): ");
}
puts("Done!");
return 0;
}
unsgined short
should be%hu
and not%u
. – ameyCUn
after reloading and seeing amey's comment.) Also, OP,n
can never be negative as it'sunsigned
. – RastaJedi%d
, not%u
, forn
, albeit still incorrect. – RastaJedi