Input matrix row values iteratively into a function

1
votes

I have a matrix which is 100x1 in size. I wish to input each row value of my matrix into a function iteratively. For example, say L1 represents row 1 of my matrix L, L2 row 2, and so on. Say my function which I seek to input each value of L into is denoted Y. Therefore I seek to input L1 into Y to Produce Y1, L2 for Y2 and so on.

I could really do with help on how to implement this in matlab?

accept Code is as follows:

load('logregdata.mat')

%%Data set X is a series of coordinates in two dimensions and t represents class labels. Data set is for a binary classification problem.

u = rand;

[w1,w2] = meshgrid(-5:0.1:5,-5:0.1:5);

w = zeros(2,1);

w_all = zeros(100,2);

%Probabilistic term of logistic classifier prob_t = 1./(1+exp(-[w1(:) w2(:)]*X'));

L = sum(log(prob_t).*repmat(t',numel(w1),1),2);

L= L + sum (log(1-prob_t).*repmat(1-t',numel(w1),1),2);

u = rand;

y = log(L/u);

Thanks for all your help in advance.

2
matlabmatrix
Why not change the function so that it can support a vector ? – obchardon
The function is simply Y=log(L/u), where u is a uniformly distributed random number – user136754
Your current code would help. Vectorization is highly dependent on the operations being performed. Is u the same for each row of L? – beaker
Please show us what you have attempted. It is difficult to ascertain what you're doing wrong without some code to provide context. – rayryeng
Thanks for the responses. I have posted the code below – user136754

2 Answers

0
votes

A 100x1 matrix is just a vector! So you can loop through the entire array like this:

for i = 1:100

      do something with Y(L1)

end
0
votes

In your code u is just a scalar, so you can use simple element-wise operations:

y = log(L./u);

which will give you a vector y in the same size of L such that y(k) = log(L(k)/u)