I'm trying to understand the following two snippets of code:
(defun make-adder1 (n) `(lambda (x) (+ ,n x)))
(defun make-adder2 (n) (lexical-let ((n n)) (lambda (x) (+ n x))))
These both seem to produce callables:
(funcall (make-adder1 3) 5) ;; returns 8
(funcall (make-adder2 3) 5) ;; returns 8
These both work. I have two main questions:
1) I don't understand the disparity in "quoting level" between the two approaches. In the first case, the lambda expression is quoted, which means the "symbol itself" is returned instead of the value. In the second case, it seems like the statement with the lambda will get evaluated, so the value of the lambda will be returned. Yet, these both work with funcall
. When using funcall
on a defun
'ed function, it has to be quoted. Is lexical-let doing some kind of quoting automatically? Isn't this, kind of surprising?
2) Reading other posts on this topic, I'm given to understand that the first approach will break down under certain circumstances and deviate from what one would expect from working with lambdas and higher order functions in other languages, because elisp has dynamic scoping by default. Can someone give a concrete example of code that makes this difference apparent and explain it?