I know that %0
contains the full path of the batch script, e.g. c:\path\to\my\file\abc.bat
I would path
to be equal to c:\path\to\my\file
How could I achieve that ?
I know that %0
contains the full path of the batch script, e.g. c:\path\to\my\file\abc.bat
I would path
to be equal to c:\path\to\my\file
How could I achieve that ?
%~dp0
will be the directory. Here's some documentation on all of the path modifiers. Fun stuff :-)
To remove the final backslash, you can use the :n,m
substring syntax, like so:
SET mypath=%~dp0
echo %mypath:~0,-1%
I don't believe there's a way to combine the %0
syntax with the :~n,m
syntax, unfortunately.
%~dp0 - return the path from where script executed
But, important to know also below one:
%CD% - return the current path in runtime, for example if you get into other folders using "cd folder1", and then "cd folder2", it will return the full path until folder2 and not the original path where script located
You can use %~dp0
, d means the drive only, p means the path only, 0 is the argument for the full filename of the batch file.
For example if the file path was C:\Users\Oliver\Desktop\example.bat then the argument would equal C:\Users\Oliver\Desktop\, also you can use the command set cpath=%~dp0 && set cpath=%cpath:~0,-1%
and use the %cpath%
variable to remove the trailing slash.
I am working on a Windows 7 machine and I have ended up using the lines below to get the absolute folder path for my bash script.
I got to this solution after looking at http://www.linuxjournal.com/content/bash-parameter-expansion.
#Get the full aboslute filename.
filename=$0
#Remove everything after \. An extra \ seems to be necessary to escape something...
folder="${filename%\\*}"
#Echo...
echo $filename
echo $folder