drawing square net in SDI MFC

Question

how can i draw square net ( like chess) in SDI MFC ? and how to determine the position for putting some more shape in specific position ? i have to use (Moveto) and (Lineto) and draw them 1 by 1 ? or using bitmap ? or easier way ? i tried in this way but it's not really smart. thank you.

COLORREF blueline = RGB(255, 0, 0);
    pen1.CreatePen(PS_SOLID, 3, blueline);
    pDC->SelectObject(&pen1);
    pDC->MoveTo(0,80);
    pDC->LineTo(1024, 80);
    pDC->SelectObject(&pen1);

Have a look here: msdn.microsoft.com/en-gb/library/windows/hardware/…. You use the CMemDC class. This is good if you want to reduce flickering. — Andrew Truckle
@AndrewTruckle: All supported versions of Windows implement double-buffering already, as is. There hardly ever is a need to render to a memory device context. — IInspectable
@AndrewTruckle: This has nothing to do with MFC. MFC merely provides wrappers around standard Windows controls and windows. Those are double-buffered by default in the Desktop Window Manager (DWM). — IInspectable

IInspectable IInspectable · Accepted Answer · 2016-06-22T14:35:57

You can draw solid rectangles by calling CDC::FillSolidRect. If your rectangles should contain a more complex pattern, use CDC::FillRect instead.

You can render a checkered board using the following pseudo-code:

for (int x = 0; x < 8; ++x) {
    for (int y = 0; y < 8; ++y ) {
        // Calculate square position and size
        int x0 = x_origin + x * square_width;
        int x1 = x_origin + (x + 1) * square_width;
        int y0 = y_origin + y * square_height;
        int y1 = y_origin + (y + 1) * square_height;
        RECT r = {x0, y0, x1, y1};
        // Pick alternating color
        COLORREF color = (x + y) & 1 ? RGB(0, 0, 0) : RGB(255, 255, 255);
        // Render square
        pDC->FillSolidRect(&r, color);
    }
}

drawing square net in SDI MFC

1 Answers