Java, XPath Expression to read all node names, node values, and attributes

Question

I need help in make an xpath expression to read all node names, node values, and attributes in an xml string. I made this:

private List<String> listOne = new ArrayList<String>();
private List<String> listTwo = new ArrayList<String>();

public void read(String xml) {
    try {
        // Turn String into a Document
        Document document = DocumentBuilderFactory.newInstance()
                .newDocumentBuilder().parse(new ByteArrayInputStream(xml.getBytes()));

        // Setup XPath to retrieve all tags and values
        XPath xPath = XPathFactory.newInstance().newXPath();
        NodeList nodeList = (NodeList) xPath.evaluate("//text()[normalize-space()='']", document, XPathConstants.NODESET);

        // Iterate through nodes
        for(int i = 0; i < nodeList.getLength(); i++) {
            Node node = nodeList.item(i);
            listOne.add(node.getNodeName());
            listTwo.add(node.getNodeValue());
            // Another list to hold attributes
        }

    } catch(Exception e) {
        LogHandle.info(e.getMessage());
    }
}

I found the expression //text()[normalize-space()=''] online; however, it doesn't work. When I get try to get the node name from listOne, it is just #text. I tried //, but that doesn't work either. If I had this XML:

<Data xmlns="Somenamespace.nsc">
    <Test>blah</Test>
    <Foo>bar</Foo>
    <Date id="2">12242016</Date>
    <Phone>
        <Home>5555555555</Home>
        <Mobile>5555556789</Mobile>
    </Phone>
</Data>

listOne[0] should hold Data, listOne[1] should hold Test, listTwo[1] should hold blah, etc... All the attributes will be saved in another parallel list.

What expression should xPath evaluate?

Note: The XML String can have different tags, so I can't hard code anything.

Update: Tried this loop:

NodeList nodeList = (NodeList) xPath.evaluate("//*", document, XPathConstants.NODESET);

// Iterate through nodes
for(int i = 0; i < nodeList.getLength(); i++) {
    Node node = nodeList.item(i);

    listOne.add(i, node.getNodeName());

    // If null then must be text node
    if(node.getChildNodes() == null)
        listTwo.add(i, node.getTextContent());
}

However, this only gets the root element Data, then just stops.

text() refers to element content. In your example XML, blah, bar and 12242016 are text nodes. So, text() probably is not what you want. — VGR
Thanks! If text() gives the element content, will node() give the nodes? — syy
I think some clarification might be needed. In XML, “node” refers to every possible piece of information in an XML document, including text, comments, processing instructions, etc., whereas “element” refers to information consisting of either a start tag and a matching end tag, or a single self-closing tag (<name … />). Do you really want to read every node, or just every element and its attributes? — VGR
Thanks for clarification. I want to read every element, any text associated with it (<Name>Flow</Name>), and its attributes if there are any. Hope I got the meanings correct. — syy

Martin Honnen Martin Honnen · Accepted Answer · 2016-06-13T20:02:18

//* will select all element nodes, //@* all attribute nodes. However, an element node does not have a meaningful node value in the DOM, so you would need to read out getTextContent() instead of getNodeValue.

As you seem to consider an element with child elements to have a "null" value I think you need to check whether there are any child elements:

    DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
    docBuilderFactory.setNamespaceAware(true);

    DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();

    Document doc = docBuilder.parse("sampleInput1.xml");

    XPathFactory fact = XPathFactory.newInstance();
    XPath xpath = fact.newXPath();

    NodeList allElements = (NodeList)xpath.evaluate("//*", doc, XPathConstants.NODESET);

    ArrayList<String> elementNames = new ArrayList<>();
    ArrayList<String> elementValues = new ArrayList<>();

    for (int i = 0; i < allElements.getLength(); i++)
    {
        Node currentElement = allElements.item(i);
        elementNames.add(i, currentElement.getLocalName());
        elementValues.add(i, xpath.evaluate("*", currentElement, XPathConstants.NODE) != null ? null : currentElement.getTextContent());
    }

    for (int i = 0; i < elementNames.size(); i++)
    {
        System.out.println("Name: " + elementNames.get(i) + "; value: " + (elementValues.get(i)));
    }

For the sample input

<Data xmlns="Somenamespace.nsc">
    <Test>blah</Test>
    <Foo>bar</Foo>
    <Date id="2">12242016</Date>
    <Phone>
        <Home>5555555555</Home>
        <Mobile>5555556789</Mobile>
    </Phone>
</Data>

the output is

Name: Data; value: null
Name: Test; value: blah
Name: Foo; value: bar
Name: Date; value: 12242016
Name: Phone; value: null
Name: Home; value: 5555555555
Name: Mobile; value: 5555556789

Java, XPath Expression to read all node names, node values, and attributes

1 Answers