Thought provoking problem (for me at least). Normally when creating a chart you have your data and then use it to create the chart. If you then copy the chart to another workbook, the values on the chart stay the same but there is "no available" data source in the new workbook. I want to create a new chart which is the average of multiple copied charts. Is this possible in excel/vba?
I can't even try recording a macro and going from there as I don't know if its possible to "average" multiple charts.
EDIT : Been doing some more thinking and am thinking if it is possible to instead of extract data into a new sheet for each chart, is it possible to average data upon extraction. If on the chart you Right click -> select data, you can see the reference to the data in the original worksheet. Is it possible to average this and print just the outcome without having to store all the data? Would still be easier to directly average charts if possible!
EDIT 2: I have reworked my data template so that matching time series data ranges is no longer an issue. Also as per the comment on averages-of-averages, the data is all of equal weight and quantity so this should not be a problem. It literally just comes down to: is there a way to take the face values of multiple charts (or graphs), and average them to form a new chart (or graph) without massive data manipulation in the original (or new) workbook?
Bounty Summary (with round numbers): Looking for a quick'ish way in VBA to create a chart which is the average of multiple charts. I have 10 types of chart on 50 separate worksheets. I'm looking to create a summary sheet with 10 charts that average the data from the same respective chart on the other 50 sheets. The key difficulty is that this is a 'presentation Workbook that all charts are copied into, all the data for each chart is in a different workbook.
EDIT 4: Data is stored in multiple time series tables that are all side by side in a main data sheet. It appears to be at the moment (as per Scott's comment) that there is no way to directly manipulate and the most likely solution will be that of data extraction/manipulation. Search still continues though :)