python - Get the position of the largest value in a multi-dimensional NumPy array

Question

How can I get get the position (indices) of the largest value in a multi-dimensional NumPy array?

Answer 1

The argmax() method should help.

Update

(After reading comment) I believe the argmax() method would work for multi dimensional arrays as well. The linked documentation gives an example of this:

>>> a = array([[10,50,30],[60,20,40]])
>>> maxindex = a.argmax()
>>> maxindex
3

Update 2

(Thanks to KennyTM's comment) You can use unravel_index(a.argmax(), a.shape) to get the index as a tuple:

>>> from numpy import unravel_index
>>> unravel_index(a.argmax(), a.shape)
(1, 0)

Answer 2

(edit) I was referring to an old answer which had been deleted. And the accepted answer came after mine. I agree that argmax is better than my answer.

Wouldn't it be more readable/intuitive to do like this?

numpy.nonzero(a.max() == a)
(array([1]), array([0]))

Or,

numpy.argwhere(a.max() == a)

Answer 3

You can simply write a function (that works only in 2d):

def argmax_2d(matrix):
    maxN = np.argmax(matrix)
    (xD,yD) = matrix.shape
    if maxN >= xD:
        x = maxN//xD
        y = maxN % xD
    else:
        y = maxN
        x = 0
    return (x,y)

Answer 4

An alternative way is change numpy array to list and use max and index methods:

List = np.array([34, 7, 33, 10, 89, 22, -5])
_max = List.tolist().index(max(List))
_max
>>> 4