119
votes

I know that in angular2 I can disable a button with the [disable] attribute, for example:

<button [disabled]="!isValid" (click)="onConfirm()">Confirm</button>

but can I do it using [ngClass] or [ngStyle] ? Like so:

<button [ngStyle]="{disabled : !isValid}" (click)="onConfirm()">Confirm</button>

Thanks.

10
here is working plnkr for the same plnkr.co/edit/MW3vT4XscWcKrDdAwBoE?p=preview - Pardeep Jain

10 Answers

184
votes

Update

I'm wondering. Why don't you want to use the [disabled] attribute binding provided by Angular 2? It's the correct way to dealt with this situation. I propose you move your isValid check via component method.

<button [disabled]="! isValid" (click)="onConfirm()">Confirm</button>

The Problem with what you tried explained below

Basically you could use ngClass here. But adding class wouldn't restrict event from firing. For firing up event on valid input, you should change click event code to below. So that onConfirm will get fired only when field is valid.

<button [ngClass]="{disabled : !isValid}" (click)="isValid && onConfirm()">Confirm</button>

Demo Here

40
votes

I would recommend the following.

<button [disabled]="isInvalid()">Submit</button>
9
votes

Yes you can

<div class="button" [ngClass]="{active: isOn, disabled: isDisabled}"
         (click)="toggle(!isOn)">
         Click me!
 </div>

https://angular.io/docs/ts/latest/api/common/NgClass-directive.html

7
votes

If you have a form then the following is also possible:

<form #f="ngForm">
    <input name="myfield" type="text" minlenght="3" required ngModel>
    <button type="submit" [disabled]="!f.valid">Submit</button>
</form>

Demo here: http://plnkr.co/edit/Xm2dCwqB9p6WygrquUGh?p=preview&open=app%2Fapp.component.ts

5
votes

Using ngClass to disabled the button for invalid form is not good practice in Angular2 when its providing inbuilt features to enable and disable the button if form is valid and invalid respectively without doing any extra efforts/logic.

[disabled] will do all thing like if form is valid then it will be enabled and if form is invalid then it will be disabled automatically.

See Example:

<form (ngSubmit)="f.form.valid" #f="ngForm" novalidate>
<input type="text" placeholder="Name" [(ngModel)]="txtName" name="txtname" #textname="ngModel" required>
<input type="button" class="mdl-button" [disabled]="!f.form.valid" (click)="onSave()" name="">

4
votes

May be below code can help:

<button [attr.disabled]="!isValid ? true : null">Submit</button>
2
votes

I tried using disabled along with click event. Below is the snippet , the accepted answer also worked perfectly fine , I am adding this answer to give an example how it can be used with disabled and click properties.

<button (click)="!planNextDisabled && planNext()" [disabled]="planNextDisabled"></button>
2
votes

If you are using reactive forms and want to disable some input associated with a form control, you should place this disabled logic into you code and call yourFormControl.disable() or yourFormControl.enable()

2
votes

I think this is the easiest way

<!-- Submit Button-->
<button 
  mat-raised-button       
  color="primary"
  [disabled]="!f.valid"
>
  Submit
</button>
1
votes
 <button [disabled]="this.model.IsConnected() == false"
              [ngClass]="setStyles()"
              class="action-button action-button-selected button-send"
              (click)= "this.Send()">
          SEND
        </button>

.ts code

setStyles() 
{
    let styles = {

    'action-button-disabled': this.model.IsConnected() == false  
  };
  return styles;
}