What is the difference between `-fpic` and `-fPIC` gcc parameters?

Question

I've already read the gcc manpage, but I still can't understand the difference between -fpic and -fPIC. Can someone explain it, in a very simple and clear way?

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Related questions:

• What does -fPIC mean when building a shared library?
• What, if any, are the implications of compiling objects with gcc -fPIC flag if they get used in executables?

Answer 1

http://tldp.org/HOWTO/Program-Library-HOWTO/shared-libraries.html

Answer 2

From the Gcc manual page:

When generating code for shared libraries, -fpic implies -msmall-data and -fPIC implies -mlarge-data.

Where:

 -msmall-data
 -mlarge-data
       When -mexplicit-relocs is in effect, static data is accessed via
       gp-relative relocations.  When -msmall-data is used, objects 8
       bytes long or smaller are placed in a small data area (the
       ".sdata" and ".sbss" sections) and are accessed via 16-bit
       relocations off of the $gp register.  This limits the size of the
       small data area to 64KB, but allows the variables to be directly
       accessed via a single instruction.

       The default is -mlarge-data.  With this option the data area is
       limited to just below 2GB.  Programs that require more than 2GB
       of data must use "malloc" or "mmap" to allocate the data in the
       heap instead of in the program's data segment.

       When generating code for shared libraries, -fpic implies
       -msmall-data and -fPIC implies -mlarge-data.