Spark: Add column to dataframe conditionally

37
votes

I am trying to take my input data:

A    B       C
--------------
4    blah    2
2            3
56   foo     3

And add a column to the end based on whether B is empty or not:

A    B       C     D
--------------------
4    blah    2     1
2            3     0
56   foo     3     1

I can do this easily by registering the input dataframe as a temp table, then typing up a SQL query.

But I'd really like to know how to do this with just Scala methods and not having to type out a SQL query within Scala.

I've tried .withColumn, but I can't get that to do what I want.

3
scalaapache-sparkapache-spark-sqlspark-dataframe

3 Answers

94
votes

Try withColumn with the function when as follows:

val sqlContext = new SQLContext(sc)
import sqlContext.implicits._ // for `toDF` and $""
import org.apache.spark.sql.functions._ // for `when`

val df = sc.parallelize(Seq((4, "blah", 2), (2, "", 3), (56, "foo", 3), (100, null, 5)))
    .toDF("A", "B", "C")

val newDf = df.withColumn("D", when($"B".isNull or $"B" === "", 0).otherwise(1))

newDf.show() shows

+---+----+---+---+
|  A|   B|  C|  D|
+---+----+---+---+
|  4|blah|  2|  1|
|  2|    |  3|  0|
| 56| foo|  3|  1|
|100|null|  5|  0|
+---+----+---+---+

I added the (100, null, 5) row for testing the isNull case.

I tried this code with Spark 1.6.0 but as commented in the code of when, it works on the versions after 1.4.0.

3
votes

My bad, I had missed one part of the question.

Best, cleanest way is to use a UDF. Explanation within the code.

// create some example data...BY DataFrame
// note, third record has an empty string
case class Stuff(a:String,b:Int)
val d= sc.parallelize(Seq( ("a",1),("b",2),
     ("",3) ,("d",4)).map { x => Stuff(x._1,x._2)  }).toDF

// now the good stuff.
import org.apache.spark.sql.functions.udf
// function that returns 0 is string empty 
val func = udf( (s:String) => if(s.isEmpty) 0 else 1 )
// create new dataframe with added column named "notempty"
val r = d.select( $"a", $"b", func($"a").as("notempty") )

    scala> r.show
+---+---+--------+
|  a|  b|notempty|
+---+---+--------+
|  a|  1|    1111|
|  b|  2|    1111|
|   |  3|       0|
|  d|  4|    1111|
+---+---+--------+
2
votes

How about something like this? 

val newDF = df.filter($"B" === "").take(1) match {
  case Array() => df
  case _ => df.withColumn("D", $"B" === "")
}

Using take(1) should have a minimal hit