Zipping files with 7z.exe

Question

I have a folder that contains a batch file named zip.bat with the following code inside:

for /d %%X in (*) do "C:\Program Files (x86)\7-Zip\7z.exe" a "%%X.zip" "%%X\"

The issue that i'm having with this bat is that it zips any folder inside the folder that contains the zip.bat but what I really want it to do is to zip text files not folders.

Can anyone guide me on what i'm doing wrong?

Thank you.

Then tell it to zip text files. You are telling it to zip the folder. — Squashman

Frank Frank · Accepted Answer · 2016-01-05T10:40:11

Your question is not very clear to me.

If you want to have each folder containing txt-files in a separate zip-file you can use:

for /d %%X in (*) do "C:\Program Files (x86)\7-Zip\7z.exe" a "%%X.zip" "%%X\*.txt"

If you want a single zip-file named containing all txt-files (with folder structure) you can use:

"C:\Program Files (x86)\7-Zip\7z.exe" a -r txtfiles-%date%.zip "*.txt"

If you want a single zip-file named containing txt-files of the current folder where your cmd/batch file is located you can use:

"C:\Program Files (x86)\7-Zip\7z.exe" a txtfiles-%date%.zip "*.txt"

Zipping files with 7z.exe

1 Answers