Scala Jackson Serialization add computed field to serialized case class

0
votes

I have a scala case class:

case class Person(name: String, age: Int) {
    def isMillenial: Boolean = age <= someConstantMillenialThreshold
}

This serializes into the following json (using the ScalaJsonFactory object mapper to serialize):

{
    name: "foo",
    age: 42
}

However I want it to be serialized as follows:

{
    name: "foo",
    age: 42,
    isMillenial: true
}

Is there any way of doing this in a simple way, preferably by using some Jackson annotation or something similar? Basically looking for any solution which doesn't involve changing the case class Person or creating new objects

1
jsonscalaserializationjackson

1 Answers

0
votes

Done! Looks like we can do this:

import com.fasterxml.jackson.annotation.JsonProperty
case class Person(name: String, age: Int) {
    @JsonProperty("isMillenial") def isMillenial: Boolean = age <= someConstantMillenialThreshold
}