WPF MVVM Change button content with loading user control

0
votes

I have a simple window with two buttons on bottom, when one button is clicked it change the view model of my main window, the name of the content button and the command.

I would like that when user click on the button change this with a loading user control i already have but i'm stacked, i don't know it's something i can implement with xaml or i need some code on my view model.

Any suggestions would be appreciated. Thanks.

1
c#wpfxamlmvvm
Both: ViewModel and View have to interact. E.g. command from button (View) will trigger property changes (ViewModel), which are bound to controls (View). You may want to put content into another View+ViewModel (UserControl and its ViewModel) and use ContentControl + datatemplates with usual binding to display it. The best appropriate solution require more details: what content is exactly you want to display, etc. – Sinatr
What about using a BusyIndicator? – Jannik
Ok, if i understood correctly i can create two ViewModel "Button" and "LoadingButton" and then switch between this two when the user click on it. The problem now is that i have two button with different content and command, how can i dynamically assign those? Right now in my view i have two buttons with relative bindings on my view model. – Babalaus

1 Answers

1
votes

You will need some code on your ViewModel to swap out the Button for the Loading control. You can either do this with binding ContentControls or with a Boolean property to set one to visible and the other to hidden while the loading happens.