I am calling Openweather map API using Swift and from the response I need to return a particular value as string.
However when I try to return the value error comes as JSON is not convertible to string.
func callWeatherServ(name:String, completion:(Dictionary<String,AnyObject>) -> Void)
{
var baseUrl: String = "http://api.openweathermap.org/data/2.5/weather"
var url: String = "\(baseUrl)?q=\(name)"
let finalUrl: NSURL = NSURL(string: url)!
let session = NSURLSession.sharedSession()
let task = session.dataTaskWithURL(finalUrl, completionHandler: {data, response, error -> Void in
if error != nil
{
// If there is an error in the web request, print it to the console
println(error.localizedDescription)
}
var err: NSError?
var jsonResult = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &err) as! NSDictionary
if err != nil
{
// If there is an error parsing JSON, print it to the console
println("JSON Error \(err!.localizedDescription)")
}
let json = JSON(jsonResult)
println("response is \(json) ")
var weathername = json["weather"][0]["main"]
if (weathername != nil)
{
return weathername
}
})
task.resume()
}
I get that since we have used closure whose return type void so we should use completion handler. But I am not aware how we can do that.
Also how we can call the function if we pass completion handler as parameter?
completion(weathername)instead ofreturn weathernamethen call your function using the completion like in my example link. Also be careful, it seems like you're parsing your JSON twice, once with NSJSONSerialization and once with SwiftyJSON... - Eric Aya