2
votes

I develop Restful web service. I want output as XML type(VXML). I try like this. I use Java 8, Maven, Jersey and same as new technology. I get details from that web address link.

this my example code for request catch

@Path("/custemerservice")
public interface CustemerService {
    @GET
    @Path("no/123")
    @Consumes({ MediaType.APPLICATION_FORM_URLENCODED })
    @Produces("text/html")
    public Response getWelcomeInfo();
}

and below this is development code

@Service
public class CustemerServiceImpl implements CustemerService {
    @Override
    public Response getWelcomeInfo() {
        Map<String, Object> map = new HashMap<String, Object>();
        map.put("user", "usul");
        List<String> l = new ArrayList<String>();
        l.add("light saber");
        l.add("fremen clothes");
        map.put("items", l);
        return Response.ok(new Viewable("/cart.jsp", map)).build();
    }
}

this is my web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">
    <display-name>MyApp</display-name>
    <listener>
        <listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
    </listener>
    <listener>
        <listener-class>org.jboss.resteasy.plugins.spring.SpringContextLoaderListener</listener-class>
    </listener>
    <listener>
        <listener-class>com.sun.jersey.spi.container.servlet.ServletContainer</listener-class>
    </listener>
    <servlet>
        <servlet-name>javax.ws.rs.core.Application</servlet-name>
        <servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>javax.ws.rs.core.Application</servlet-name>
        <url-pattern>/resteasy/*</url-pattern>
    </servlet-mapping>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>WEB-INF/spring-hibernate-resteasy.xml</param-value>
    </context-param>
    <context-param>
        <param-name>resteasy.servlet.mapping.prefix</param-name>
        <param-value>/resteasy</param-value>
    </context-param>
    <context-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.ezakus.web</param-value>
    </context-param>
    <context-param>
        <param-name>com.sun.jersey.config.property.JSPTemplatesBasePath</param-name>
        <param-value>/WEB-INF/jsp</param-value>
    </context-param>
    <context-param>
        <param-name>com.sun.jersey.config.property.WebPageContentRegex</param-name>
        <param-value>/(resources|(WEB-INF/jsp))/.*</param-value>
    </context-param>
    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
    </welcome-file-list>

</web-app>

and I edit pom.xml for that part development

        <dependency>
            <groupId>com.sun.jersey</groupId>
            <artifactId>jersey-server</artifactId>
            <version>1.9</version>
        </dependency>
        <dependency>
            <groupId>com.sun.jersey.contribs</groupId>
            <artifactId>jersey-multipart</artifactId>
            <version>1.9</version>
        </dependency>
        <dependency>
            <groupId>com.fasterxml.jackson.jaxrs</groupId>
            <artifactId>jackson-jaxrs-json-provider</artifactId>
            <version>2.5.1</version>
        </dependency>

        <dependency>
            <groupId>jstl</groupId>
            <artifactId>jstl</artifactId>
            <version>1.2</version>
            <scope>compile</scope>
        </dependency>
        <dependency>
            <groupId>taglibs</groupId>
            <artifactId>standard</artifactId>
            <version>1.1.2</version>
            <scope>compile</scope>
        </dependency>

I try to run project using tomcat 8 in eclipse. I got error like this how to solve it.

HTTP Status 500 - Servlet execution threw an exception

type Exception report

message Servlet execution threw an exception

description The server encountered an internal error that prevented it from fulfilling this request.

exception

javax.servlet.ServletException: Servlet execution threw an exception org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

root cause

java.lang.NoSuchMethodError: org.jboss.resteasy.specimpl.BuiltResponse.getHeaders()Ljavax/ws/rs/core/MultivaluedMap; org.jboss.resteasy.core.ServerResponseWriter.setDefaultContentType(ServerResponseWriter.java:186) org.jboss.resteasy.core.ServerResponseWriter.writeNomapResponse(ServerResponseWriter.java:46) org.jboss.resteasy.core.SynchronousDispatcher.writeResponse(SynchronousDispatcher.java:427) org.jboss.resteasy.core.SynchronousDispatcher.invoke(SynchronousDispatcher.java:376) org.jboss.resteasy.core.SynchronousDispatcher.invoke(SynchronousDispatcher.java:179) org.jboss.resteasy.plugins.server.servlet.ServletContainerDispatcher.service(ServletContainerDispatcher.java:220) org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:56) org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:51) javax.servlet.http.HttpServlet.service(HttpServlet.java:729) org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

note The full stack trace of the root cause is available in the Apache Tomcat/8.0.23 logs. Apache Tomcat/8.0.23

this is eclipse log .

Thanks.

2
Do you call this API from the browser and get this exception? What is that URL?Puneet Pandey
localhost:8080/MyApp/resteasy/custemerservice/no/123 this is browser get Url. but get out put as that error.Thilina Sampath

2 Answers

6
votes

Looks like you use a version 1 of resteasy-jaxrs.jar. The Method getHeaders()Ljavax/ws/rs/core/MultivaluedMap;was introduced in version 2.

So you have to change to version 2 of the resteasy-jaxrs.jar which contains the class org.jboss.resteasy.specimpl.BuiltResponse

0
votes

It didn´t recognize the annotation @Produces("text/html").

Use Response.status(Response.Status.OK).type(MediaType.TEXT_HTML)