Unicode Regular Expressions - Fails at 343 characters

1
votes

I am using the regular expression below to weed out any non-Latin characters. As a result, I found that if I use a string larger than 342 characters, the function fails, everything aborts, and the website connection is reset.

I narroed it down to the \p{P} unicode character property, which matches any punctuation character.

Does anyone know/see where the problem lies, exactly?

preg_match('/^([\p{P}\p{S}&\p{Latin}0-9]|\s)*$/u', 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa');

1
regexunicodecharacter-properties
hy are you eeding out all non-latin characters? Ho ould your text look if you removed all instances of certain characters from English text? – Greg Hewgill
@Greg : How's that 'w' key working for you? – Stephen
@Greg, I basically want people to use Latin characters only. It does the job except in the case where there are more than 342 characters. I'm not sure why. Thus the question. – KcYxA

1 Answers

1
votes

If you're "weeding out" non-Latin characters, why not just do this:

preg_replace('/[^\p{Latin}]+/u', '', $s)

EDIT: Okay, so you're trying to validate the input. I was going to say, use this:

preg_match('/^[\p{Latin}]+$/u', $s)

...but it turns out that only matches Latin letters. I was thinking of Java's undocumented shorthand, \p{L1}, which matches everything in the Latin1 (ISO-8859-1) character set, but in PHP you have to spell it out:

preg_match('/^[\x00-\xFF]+$/u', $s)