Timeout jQuery effects

101
votes

I am trying to have an element fade in, then in 5000 ms fade back out again. I know I can do something like:

setTimeout(function () { $(".notice").fadeOut(); }, 5000);

But that will only control the fade out, would I add the above on the callback?

7
jquerytimeout

7 Answers

197
votes

Update: As of jQuery 1.4 you can use the .delay( n ) method. http://api.jquery.com/delay/

$('.notice').fadeIn().delay(2000).fadeOut('slow');

Note: $.show() and $.hide() by default are not queued, so if you want to use $.delay() with them, you need to configure them that way:

$('.notice')
    .show({duration: 0, queue: true})
    .delay(2000)
    .hide({duration: 0, queue: true});

You could possibly use the Queue syntax, this might work: 

jQuery(function($){ 

var e = $('.notice'); 
e.fadeIn(); 
e.queue(function(){ 
  setTimeout(function(){ 
    e.dequeue(); 
  }, 2000 ); 
}); 
e.fadeOut('fast'); 

});

or you could be really ingenious and make a jQuery function to do it.

(function($){ 

  jQuery.fn.idle = function(time)
  { 
      var o = $(this); 
      o.queue(function()
      { 
         setTimeout(function()
         { 
            o.dequeue(); 
         }, time);
      });
  };
})(jQuery);

which would ( in theory , working on memory here ) permit you do to this: 

$('.notice').fadeIn().idle(2000).fadeOut('slow');
23
votes

I just figured it out below:

$(".notice")
   .fadeIn( function() 
   {
      setTimeout( function()
      {
         $(".notice").fadeOut("fast");
      }, 2000);
   });

I will keep the post for other users!

14
votes

Great hack by @strager. Implement it into jQuery like this:

jQuery.fn.wait = function (MiliSeconds) {
    $(this).animate({ opacity: '+=0' }, MiliSeconds);
    return this;
}

And then use it as:

$('.notice').fadeIn().wait(2000).fadeOut('slow');
11
votes

You can do something like this:

$('.notice')
    .fadeIn()
    .animate({opacity: '+=0'}, 2000)   // Does nothing for 2000ms
    .fadeOut('fast');

Sadly, you can't just do .animate({}, 2000) -- I think this is a bug, and will report it.

7
votes

Ben Alman wrote a sweet plugin for jQuery called doTimeout. It has a lot of nice features!

Check it out here: jQuery doTimeout: Like setTimeout, but better.

5
votes

To be able to use it like that, you need to return this. Without the return, fadeOut('slow'), will not get an object to perform that operation on.

I.e.:

  $.fn.idle = function(time)
  {
      var o = $(this);
      o.queue(function()
      {
         setTimeout(function()
         {
            o.dequeue();
         }, time);
      });
      return this;              //****
  }

Then do this:

$('.notice').fadeIn().idle(2000).fadeOut('slow');
1
votes

This can be done with only a few lines of jQuery:

$(function(){
    // make sure img is hidden - fade in
    $('img').hide().fadeIn(2000);

    // after 5 second timeout - fade out
    setTimeout(function(){$('img').fadeOut(2000);}, 5000);
});​

see the fiddle below for a working example...

http://jsfiddle.net/eNxuJ/78/