Number of arguments in macro definition

Question

I have some templated function which has different number of arguments due to the template-type. This function is wrapped with macro definition.

#define SomeTemplate(TemplateType, Arguments) someFunc<TemplateType>(Arguments);

Everything is okay when I'm using only one argument for function calling, but I need in more. I looked at boost it does such things through definition of different macros, like this:

#define TEMP_1(Arg1) someFunc<Template>(Arg1);
#define TEMP_2(Arg1, Arg2) someFunc<Template>(Arg1, Arg2);
#define TEMP_3(Arg1, Arg2, Arg3) someFunc<Template>(Arg1, Arg2, Arg3);

But this code marked as portable for compilers. There is way to use some defines with any number of arguments. How can I do that?

Why do you need this at all? Why not just use the templated function directly, without macros? — user319799
@doublep because calling is a lot bigger and takes more place. I've simplied it here. — Max Frai

Necrolis Necrolis · Accepted Answer · 2010-06-20T22:14:39

the only way to do that us using __VA__ARGS__ in the macro definations, however, its not as portable, beacuse older compilers like VC6 doesn't support var arg'ed macros, see: MSVC GCC

Number of arguments in macro definition

1 Answers