I am working with data from csv files that will all look the same so I am hoping to come up with a code that can be easily applied to all of them. However, sadly enough I am failing at step one :-(.
The csv files have the date and time saved in one column, so when I import them with read.csv that column gets read as a chr. How can I most easily convert this into a date that I then can use for plotting and analysis?
Here is what I tried:
load the data --> will save the date and time as chr under mydata$Date.Time (e.g. 1/1/15 0:00)
mydata<-read.csv(file.choose(), stringsAsFactors = FALSE,
strip.white = TRUE,
na.strings = c("NA",""), skip=16,
header=TRUE)
separate the Date.Time into Date and Time:
new <- do.call( rbind , strsplit( as.character( mydata$Date.Time ) , " " ) )
add these two back to the df mydata:
cbind( mydata , Date = new[,2] , Time = new[,1] )
convert Date into a date format via as.Date:
mydata$Date <- as.Date(new[,1], format="")
So this works fine for the date however I am stuck with the time, I tried this:
mydata$Time <- format(as.POSIXct(new[,2], format="%H:%M"))
this gives me the following error:
Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format
I wonder if there is a smarter way of doing this? Reading in time and date seems to be one of the substantial tasks that I would like to understand. Is there a way of R directly recognizing the date and time from the csv? Or is it generally smarter to generate a time vector by its own, if so how would I do that?
Thanks so much for your help. Sandra