From my understanding, the currently accepted answer only changes the order of the factor levels, not the actual labels (i.e., how the levels of the factor are called). To illustrate the difference between levels and labels, consider the following example:
Turn cyl into factor (specifying levels would not be necessary as they are coded in alphanumeric order):
mtcars2 <- mtcars %>% mutate(cyl = factor(cyl, levels = c(4, 6, 8)))
mtcars2$cyl[1:5]
#[1] 6 6 4 6 8
#Levels: 4 6 8
Change the order of levels (but not the labels itself: cyl is still the same column)
mtcars3 <- mtcars2 %>% mutate(cyl = factor(cyl, levels = c(8, 6, 4)))
mtcars3$cyl[1:5]
#[1] 6 6 4 6 8
#Levels: 8 6 4
all(mtcars3$cyl==mtcars2$cyl)
#[1] TRUE
Assign new labels to cyl The order of the labels was: c(8, 6, 4), hence we specify new labels as follows:
mtcars4 <- mtcars3 %>% mutate(cyl = factor(cyl, labels = c("new_value_for_8",
"new_value_for_6",
"new_value_for_4" )))
mtcars4$cyl[1:5]
#[1] new_value_for_6 new_value_for_6 new_value_for_4 new_value_for_6 new_value_for_8
#Levels: new_value_for_8 new_value_for_6 new_value_for_4
Note how this column differs from our first columns:
all(as.character(mtcars4$cyl)!=mtcars3$cyl)
#[1] TRUE
#Note: TRUE here indicates that all values are unequal because I used != instead of ==
#as.character() was required as the levels were numeric and thus not comparable to a character vector
More details:
If we were to change the levels of cyl using mtcars2 instead of mtcars3, we would need to specify the labels differently to get the same result. The order of labels for mtcars2 was: c(4, 6, 8), hence we specify new labels as follows
#change labels of mtcars2 (order used to be: c(4, 6, 8)
mtcars5 <- mtcars2 %>% mutate(cyl = factor(cyl, labels = c("new_value_for_4",
"new_value_for_6",
"new_value_for_8" )))
Unlike mtcars3$cyl and mtcars4$cyl, the labels of mtcars4$cyl and mtcars5$cyl are thus identical, even though their levels have a different order.
mtcars4$cyl[1:5]
#[1] new_value_for_6 new_value_for_6 new_value_for_4 new_value_for_6 new_value_for_8
#Levels: new_value_for_8 new_value_for_6 new_value_for_4
mtcars5$cyl[1:5]
#[1] new_value_for_6 new_value_for_6 new_value_for_4 new_value_for_6 new_value_for_8
#Levels: new_value_for_4 new_value_for_6 new_value_for_8
all(mtcars4$cyl==mtcars5$cyl)
#[1] TRUE
levels(mtcars4$cyl) == levels(mtcars5$cyl)
#1] FALSE TRUE FALSE
dat %>% mutate(x=factor(x, labels='B'))BTW, the pipe operator is not correct in your code - akrunmagrittror other packages, but why do you need to go through this route. It is very easy to dolevels(dat$x) <- 'B'- akrundat <- data.frame(x = factor(c('A', 'B', 'A')), y = c(1:3)); levels(dat$x) <- c('b', 'a', 'b'); dat- jraab