Passing a URL variable into xsl in sharepoint 2013

Question

I use xsl to reformat a list in sharepoint 2013 and I want to implement paging in the new list. So, first I want to know how to pass parameters from the url and read it from xsl.

https://stackoverflow.com/search.aspx?page=2

I want to get "page" value.

I use this code , but never work for me.

 <xsl:param name="page"/>

and I read it like

<xsl:value-of select="$page" />

I almost finish my work and I want to just know how to read the URL variable .

Answer 1

Use @page instead of $page

<xsl:value-of select="@page" />

Answer 2

It work for me after I modify the original view xml from sharepoint physical folder under XSL (main.xsl).

I think it related to security problem, and when I create external xsl file and liked it with sharepoint list it will be not have the full trust !!