8
votes

I am trying to do a web application and have a problem: I don't know how to open a text file with Java that is saved in the resource folder:

text file saved in the resource folder

 String relativeWebPath ="/src/main/resources/words.txt";  //Import der des Textdoumentes
 String absoluteDiskPath = getServletContext().getRealPath(relativeWebPath);
 File f = new File(absoluteDiskPath);

(The file words.txt)

As you can see on the image I am trying to access words.txt but it isn't working. Any ideas?

4
/src/main/resources/, though present in your project directory structure, is probably not a part of the Web path. - William Price
Thanks for your answer. /src/main/resources/ is not working. How should I change the directory structure? - Träumerei

4 Answers

9
votes

Try this.

InputStream is = getClass().getClassLoader()
                         .getResourceAsStream("/words.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(is));
1
votes

For best practice, and avoid these problems, put text file (words.txt) to WEB_INF folder (this is secure folder for resources). Then:

ServletContext context = getContext();
InputStream resourceContent = context.getResourceAsStream("/WEB-INF/words.txt");

Reference: https://stackoverflow.com/a/4342095/3728901

0
votes

Use this code to find the path to the file you want to open.

import java.net.URL;

[...]

URL url = this.getClass().getResource("/words.txt");
String absoluteDiskPath = url.getPath();
0
votes

If you want to access in some other class, like you have a utility package and in that, you have a ReadFileUtil.java class which opens and reads the file, you can do it in the following way:

public class ReadFileUtil {

        URL url = ReadFileUtil.class.getResource("/"+yourFileName);
        File file = new File(url.getPath());

    }