how to move position of an array element only in one direction

Question

Suppose I have a 4*4 matrix and I prompt to enter some position and that position is 4,1

(upward movement)now I want to iterate through positions (3,1) - (2,1) - (1,1) , check those values and sometimes I must change those values and finally print a new matrix with updates values

similarly how to iterate through (4,3) , (3,3) (2,3) , (1,3) if some one enters the position as 4,4 (left movement)

I have tried , this so far ..

for(rowCount = 0; rowCount < rows; rowCount++) {
    for(columnCount = 0; columnCount < columns; columnCount++){
        if(rowCount == specialRow && columnCount == specialColumn)

        {
            if(board[rowCount][columnCount] = 1 )
            {
                printf("%d \t",board[rowCount][columnCount]);
                board[rowCount][columnCount] = 0 ;

            }
        }

        for(rowCount = 0; rowCount < rows; rowCount++) {
            for(columnCount = 0; columnCount < columns; columnCount++)
                printf("%d \t",board[rowCount][columnCount]);

            printf("\n");
        }
    }
}

rows means maximum rows
columns means maximum columns
rowCount for row iteration
columnCount for colum iteration
specialRow and sepcialColumn for the new position entered (from this position we have scan values in upward/left/backward directions) .

i did'nt get it. are you saying to change my statement in if condition as board[rowCount][columnCount] = 1 to board[rowCount][columnCount] = --> == 0 — Mann
lol, No he is not suggesting that. Quite rightly - he is suggesting you examine your use of = and perhaps consider == — Grantly
To trick yourself out of doing such mistakes again you might like to start using Yoda Conditions: en.wikipedia.org/wiki/Yoda_conditions — alk

Gopi Gopi · Accepted Answer · 2014-12-25T11:21:01

Updating your array first based on some condition let's say the input is 4 4 so you should be doing

for(rowCount = 0; rowCount < rows; rowCount++) {

    for(columnCount = 0; columnCount < columns; columnCount++){
        if(columnCount == (specialColumn-1))

        {
            if(board[rowCount][columnCount] == 1 )
            {
                printf("%d \t",board[rowCount][columnCount]);
                board[rowCount][columnCount] = 0 ;

            }
        }
}
}

Now assuming the required modifications are made to your matrix print them out seperately

   for(rowCount = 0; rowCount < rows; rowCount++) {
   for(columnCount = 0; columnCount < columns; columnCount++)
     printf("%d \t",board[rowCount][columnCount]);

     printf("\n");
    }

how to move position of an array element only in one direction

1 Answers