Regex for numbers only

Question

I haven't used regular expressions at all, so I'm having difficulty troubleshooting. I want the regex to match only when the contained string is all numbers; but with the two examples below it is matching a string that contains all numbers plus an equals sign like "1234=4321". I'm sure there's a way to change this behavior, but as I said, I've never really done much with regular expressions.

string compare = "1234=4321";
Regex regex = new Regex(@"[\d]");

if (regex.IsMatch(compare))
{ 
    //true
}

regex = new Regex("[0-9]");

if (regex.IsMatch(compare))
{ 
    //true
}

In case it matters, I'm using C# and .NET2.0.

Answer 1

Use the beginning and end anchors.

Regex regex = new Regex(@"^\d$");

Use "^\d+$" if you need to match more than one digit.

---

Note that "\d" will match [0-9] and other digit characters like the Eastern Arabic numerals ٠١٢٣٤٥٦٧٨٩. Use "^[0-9]+$" to restrict matches to just the Arabic numerals 0 - 9.

---

If you need to include any numeric representations other than just digits (like decimal values for starters), then see @tchrist's comprehensive guide to parsing numbers with regular expressions.

Answer 2

Your regex will match anything that contains a number, you want to use anchors to match the whole string and then match one or more numbers:

regex = new Regex("^[0-9]+$");

The ^ will anchor the beginning of the string, the $ will anchor the end of the string, and the + will match one or more of what precedes it (a number in this case).

Answer 3

If you need to tolerate decimal point and thousand marker

var regex = new Regex(@"^-?[0-9][0-9,\.]+$");

You will need a "-", if the number can go negative.

Answer 4

It is matching because it is finding "a match" not a match of the full string. You can fix this by changing your regexp to specifically look for the beginning and end of the string.

^\d+$

Answer 5

This works with integers and decimal numbers. It doesn't match if the number has the coma thousand separator ,

"^-?\\d*(\\.\\d+)?$"

some strings that matches with this:

894
923.21
76876876
.32
-894
-923.21
-76876876
-.32

some strings that doesn't:

hello
9bye
hello9bye
888,323
5,434.3
-8,336.09
87078.

Answer 6

Perhaps my method will help you.

    public static bool IsNumber(string s)
    {
        return s.All(char.IsDigit);
    }

Answer 7

Sorry for ugly formatting. For any number of digits:

[0-9]*

For one or more digit:

[0-9]+

Answer 8

If you need to check if all the digits are number (0-9) or not,

^[0-9]+$

Matches

1425
0142
0
1

And does not match

154a25
1234=3254

Answer 9

^\d+$, which is "start of string", "1 or more digits", "end of string" in English.

Answer 10

Here is my working one:

^(-?[1-9]+\\d*([.]\\d+)?)$|^(-?0[.]\\d*[1-9]+)$|^0$

And some tests

Positive tests:

string []goodNumbers={"3","-3","0","0.0","1.0","0.1","0.0001","-555","94549870965"};

Negative tests:

string []badNums={"a",""," ","-","001","-00.2","000.5",".3","3."," -1","--1","-.1","-0"};

Checked not only for C#, but also with Java, Javascript and PHP

Answer 11

While non of the above solutions was fitting my purpose, this worked for me.

var pattern = @"^(-?[1-9]+\d*([.]\d+)?)$|^(-?0[.]\d*[1-9]+)$|^0$|^0.0$";
return Regex.Match(value, pattern, RegexOptions.IgnoreCase).Success;

Example of valid values:

"3",
"-3",
"0",
"0.0",
"1.0",
"0.7",
"690.7",
"0.0001",
"-555",
"945465464654"

Example of not valid values:

"a",
"",
" ",
".",
"-",
"001",
"00.2",
"000.5",
".3",
"3.",
" -1",
"--1",
"-.1",
"-0",
"00099",
"099"

Answer 12

Another way: If you like to match international numbers such as Persian or Arabic, so you can use following expression:

Regex = new Regex(@"^[\p{N}]+$");

To match literal period character use:

Regex = new Regex(@"^[\p{N}\.]+$");

Answer 13

Regex for integer and floating point numbers:

^[+-]?\d*\.\d+$|^[+-]?\d+(\.\d*)?$

A number can start with a period (without leading digits(s)), and a number can end with a period (without trailing digits(s)). Above regex will recognize both as correct numbers.

A . (period) itself without any digits is not a correct number. That's why we need two regex parts there (separated with a "|").

Hope this helps.

Answer 14

Use beginning and end anchors.

 Regex regex = new Regex(@"^\d$");

Use "^\d+$" if you need to match more than one digit.

Answer 15

I think that this one is the simplest one and it accepts European and USA way of writing numbers e.g. USA 10,555.12 European 10.555,12 Also this one does not allow several commas or dots one after each other e.g. 10..22 or 10,.22 In addition to this numbers like .55 or ,55 would pass. This may be handy.

^([,|.]?[0-9])+$

Answer 16

If you want to extract only numbers from a string the pattern "\d+" should help.

Answer 17

 console.log(/^(0|[1-9][0-9]*)$/.test(3000)) // true

Answer 18

The following regex accepts only numbers (also floating point) in both English and Arabic (Persian) languages (just like Windows calculator):

^((([0\u0660\u06F0]|([1-9\u0661-\u0669\u06F1-\u06F9][0\u0660\u06F0]*?)+)(\.)[0-9\u0660-\u0669\u06F0-\u06F9]*)|(([0\u0660\u06F0]?|([1-9\u0661-\u0669\u06F1-\u06F9][0\u0660\u06F0]*?)+))|\b)$

Above regex accepts the following patterns:

11
1.2
0.3
۱۲
۱.۳
۰.۲
۲.۷

Above regex don't accept the following patterns:

3.
.3
0..3
.۱۲

Answer 19

Regex regex = new Regex ("^[0-9]{1,4}=[0-9]{1,4]$")