I am using xslt 1.0 My input xml is as below
<?xml version="1.0" encoding="UTF-8"?>
<Employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >
<FirstName>John</FirstName>
<LastName>Peter</LastName>
<Initial>T</Initial>
<Spouse>
<FirstName>Rita</FirstName>
<LastName>Hudson</LastName>
</Spouse>
</Employee>
I an trying to write a xsl to produce below output...
<?xml version="1.0" encoding="UTF-8"?>
<ArrayOfstringVariable xmlns="http://schemas.abc.org/2004/07/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<stringVariable>
<name>ServerName</name>
<value>tmn.eu.com</value>
</stringVariable>
<stringVariable>
<name>EmpFirstName</name>
<value>John</value>
</stringVariable>
<stringVariable>
<name>EmpLastName</name>
<value>Peter</value>
</stringVariable>
<stringVariable>
<name>SpouseFirstName</name>
<value>Rita</value>
</stringVariable>
<stringVariable>
<name>SpouseLastName</name>
<value>Hudson</value>
</stringVariable>
</ArrayOfstringVariable>
The output xml contains ArrayOfstringVariable stringVariable name value pair.. The name is hardcoded and the value is from input xml.. Name value "ServerName" is hardcoded.
I tried with xsl code below but it create name value pair with all the elements from input xml
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" omit-xml-declaration="no"
encoding="UTF-8" indent="yes" />
<xsl:template match="Employee">
<ArrayOfstringVariable>
<xsl:apply-templates select="*"/>
</ArrayOfstringVariable>
</xsl:template>
<xsl:template match="*">
<stringVariable>
<name>
<xsl:value-of select="local-name()"/>
</name>
<value>
<xsl:value-of select="."/>
</value>
</stringVariable>
</xsl:template>
</xsl:stylesheet>
Can anyone help me to write xsl to produce above output?
Thanks in advance