average 3d matrix matlab using reshape

Question

I have a 27x38x8760 matrix where the 27x38 represents a grid and the 8760 hours of the year. I would like to make daily avarages for the grid so that my resulting matrix is 27x38x365. I was using reshape for 2 dimensional matrix but is there a posibily to use it also for 3d? kind regards Matthias

Answer 1

Assuming A to be the input matrix, see if this works for you -

[m,n,r] = size(A)
daily_avg = squeeze(mean(reshape(A,m,n,24,[]),3))

Or avoid squeeze with permute -

daily_avg = mean(permute(reshape(A,m,n,24,[]),[1 2 4 3]),4)

Answer 2

You can also use a loop,

A = rand([27 38 8760]);
for i = 1 : 24 :8760
    A_avg(:,:,ceil(i / 24)) = mean(A(:,:,i : i + 23),3);
end