4
votes

I have a Model, subclass of NSObject, looks like as below.

class ConfigDao: NSObject {
    var categoriesVer : Int32 = Int32()
    var fireBallIP : String =  String ()
    var fireBallPort : Int32 = Int32()
    var isAppManagerAvailable : Bool = Bool()
    var timePerQuestion : String = String ()
    var isFireballAvailable : Bool = Bool ()
}

I have download NSMutableData and made JSON from it using NSJSONSerialization.

My Code is

func parserConfigData (data :NSMutableData) -> ConfigDao{

        var error : NSError?
        var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &error) as NSDictionary

        var configDao : ConfigDao = ConfigDao()

        println("Print Config \(json)")

        configDao.categoriesVer = json["CategoriesVer"] as Int32
        configDao.fireBallIP = json["FireBallIP"] as String
        configDao.fireBallPort = json["FireBallPort"] as Int32
        configDao.isAppManagerAvailable = json["IsAppManagerAvailable"] as Bool
        configDao.timePerQuestion = json["TimePerQuestion"] as String
        configDao.isFireballAvailable = json["IsFireballAvailable"] as Bool

        return configDao

    }

I get error

Type '`Int32`' does not conform  to protocol 'AnyObject' 

where I used Int32.

Image Below

enter image description here

Thanks

1

1 Answers

13
votes

Int32 cannot be automatically bridged from Objective-C NSNumber.

See this document:

All of the following types are automatically bridged to NSNumber:

  • Int
  • UInt
  • Float
  • Double
  • Bool

So you have to do like this:

configDao.categoriesVer = Int32(json["CategoriesVer"] as Int)

BTW, why you use Int32? If you don't have any specific reason, you should use Int.