How does this "hello world!" program work?

23
votes
int main(void)
{ 
    return('yes', *"no", **main, *********printf) ("hello world!\n") *0; 
}

outputs hello world!, but how does it actually work?

2
cobfuscation
return('yes', *"no", **main, *********printf) ("Its magical!\n") *0; By the way, i compiled it and it actually works ._. – Warty
you have a strange style to write software!You will never receive a job at me. :-) – Oleg
C is really a perverted language :-) – Darin Dimitrov
As a pedantic remark, in ANSI C (in C89/90 as well) calling a variadic function (printf in this case) without declaring a prototype first is undefined behavior. So, from the pedantic point of view your program works only accidentally. You need to include stdio.h for it to become a defined C program. – AnT

2 Answers

46
votes

Two things really:

  1. Function pointers don't dereference the same as other pointers. *main == main
  2. A comma separated list returns the value of the last element in the list

So if we simplify the pointers:

int main(void)
{ 
    return('yes', *"no", main, printf) ("hello world!\n") *0; 
}

And using the last element in the list as the value of the list

int main(void)
{ 
    return printf("hello world!\n") *0; 
}

printf returns the number of characters printed

int main(void)
{ 
    return 13 *0; 
}

And 13*0 is left as an exercise to the reader.

12
votes
('yes', *"no", **main, *********printf)

will evaluate to *********printf, because comma operator evaluates its operands and returns value of last expression. *********printf is equal to printf, as dereferencing function pointer results in the same function pointer; it does nothing.

Next, result of first parenthesis, printf, is applied to ("hello world!\n") which results in text printed to screen. printf function returns number of characters written. That number is then multiplied with 0 and product is returned by main function.