Umbraco count active content pages

Question

I would like to get a count of pages in nodes in an Umbraco site with output something like this:

Root (9 subnodes)
- First Folder (4 subnodes)
  - document 1
  - document 2
  - document 3
  - document 4
- Second Folder (3 subnodes)
  - document 1
  - document 2
  - document 3

Basically I am trying to see how much active content there is in a given site and come up with a way to divide the work. Is there a reasonable way to get this information?

ericdc ericdc · Accepted Answer · 2014-10-13T15:07:48

This worked for me:

Descendants.cs in App_Code folder

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using umbraco.presentation;
using umbraco.presentation.nodeFactory;

public static class ExtensionMethods
{
    public static IEnumerable<Node> AllDescendants(this Node node)
    {
        foreach (Node child in node.Children)
        {
            yield return child;

            foreach (Node grandChild in child.AllDescendants())
                yield return grandChild;
        }
    }
}

Razor View

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage
@using umbraco.presentation.nodeFactory;
@{
   Layout = "";
}

@functions{
   public string CreateSitemap()
   {
        var temp = "<ul class='collapsibleList'>" + sitemap(-1) + "</ul>" + Environment.NewLine;
       return temp;
   }

public string sitemap(int nodeID)
{
    var rootNode = new umbraco.presentation.nodeFactory.Node(nodeID);
    var sitemapstring = "<li>" + rootNode.Name + " (" + rootNode.AllDescendants().Count() + ") <span style='font-size:9px'>" + rootNode.NodeTypeAlias + "</span></li>" + Environment.NewLine;

if (rootNode.Children.Count > 0)
{
    sitemapstring += "<ul>" + Environment.NewLine;
    sitemapstring = rootNode.Children.Cast<Node>().Aggregate(sitemapstring, (current, node) => current + sitemap(node.Id));
    sitemapstring += "</ul>" + Environment.NewLine;
}
return sitemapstring;
}
}
<body>
 @Html.Raw(CreateSitemap())
</body>

Umbraco count active content pages

1 Answers