CakePHP Pagination won't allow public $paginate variable to change depending on conditions

Question

I'm using CakePHP v2.4.1, and I'm trying to have two separate models be paginated on the same page, through the same controller action (index)

I want to have a NewsPost paginated on a single page, and the EventPost also paginated separately on the same page. Is this bad practice, or is it possible to set conditions to change the $this->paginate variable to paginate properly depending on which model it is on?

My Controller looks like this:

public $uses = array(
    'NewsPost',
    'NewsPostComment',
    'EventPost',
    'EventPostComment'
);

public $paginate = array(
'limit' => 9,
'order' => array(
    'NewsPost.created' => 'desc'
), 
'recursive' => 1,
);

public function index() {       

  $this->paginate = array(
    'limit' => 1,
    'order' => array(
        'EventPost.created' => 'desc'
    ), 
    'recursive' => 1,
  ); 

$this->Paginator->settings = $this->paginate;
$newsPosts = $this->paginate('NewsPost');

$eventPosts = $this->EventPost->find('all');
$this->set(array('newsPosts' => $newsPosts, 'eventPosts' => $eventPosts));

The built-in cake paginator does not seem to allow for the options of paginating separate models, or am I wrong?

Here is the view for pagination:

<?php 
$params = $this->Paginator->params();
if ($params['count'] > 0): ?>
<div class="pagination-totals pull-left">
    <?php echo $this->Paginator->counter(array('format' => __('{:start} to {:end} of {:count}'))) ?>
</div>
<?php endif; ?>
<?php echo $this->Paginator->numbers(array(
    'class' => 'pull-right',
    'prev'     => '<',
    'next'     => '>',
)); 
?>

The problem is, when I choose page two for the NewsPost, it switches to page two for the EventPost, so how can I differentiate between both separate models on the same page using CakePHP pagination?

Thanks

MOHA MOHA · Accepted Answer · 2014-08-31T09:46:18

You have just one params named page in your page so the result in normal.

You have to handle this with ajax request and separated actions

CakePHP Pagination won't allow public $paginate variable to change depending on conditions

1 Answers