270
votes

How can I convert NSRange to Range<String.Index> in Swift?

I want to use the following UITextFieldDelegate method:

    func textField(textField: UITextField!,
        shouldChangeCharactersInRange range: NSRange,
        replacementString string: String!) -> Bool {

textField.text.stringByReplacingCharactersInRange(???, withString: string)

enter image description here

15
Thank you, Apple, for giving us the new Range class, but then not updating of any of the string utility classes, such as NSRegularExpression, to use them! – puzzl

15 Answers

273
votes

The NSString version (as opposed to Swift String) of replacingCharacters(in: NSRange, with: NSString) accepts an NSRange, so one simple solution is to convert String to NSString first. The delegate and replacement method names are slightly different in Swift 3 and 2, so depending on which Swift you're using:

Swift 3.0

func textField(_ textField: UITextField,
               shouldChangeCharactersIn range: NSRange,
               replacementString string: String) -> Bool {

  let nsString = textField.text as NSString?
  let newString = nsString?.replacingCharacters(in: range, with: string)
}

Swift 2.x

func textField(textField: UITextField,
               shouldChangeCharactersInRange range: NSRange,
               replacementString string: String) -> Bool {

    let nsString = textField.text as NSString?
    let newString = nsString?.stringByReplacingCharactersInRange(range, withString: string)
}
379
votes

As of Swift 4 (Xcode 9), the Swift standard library provides methods to convert between Swift string ranges (Range<String.Index>) and NSString ranges (NSRange). Example:

let str = "aπŸ‘ΏbπŸ‡©πŸ‡ͺc"
let r1 = str.range(of: "πŸ‡©πŸ‡ͺ")!

// String range to NSRange:
let n1 = NSRange(r1, in: str)
print((str as NSString).substring(with: n1)) // πŸ‡©πŸ‡ͺ

// NSRange back to String range:
let r2 = Range(n1, in: str)!
print(str[r2]) // πŸ‡©πŸ‡ͺ

Therefore the text replacement in the text field delegate method can now be done as

func textField(_ textField: UITextField,
               shouldChangeCharactersIn range: NSRange,
               replacementString string: String) -> Bool {

    if let oldString = textField.text {
        let newString = oldString.replacingCharacters(in: Range(range, in: oldString)!,
                                                      with: string)
        // ...
    }
    // ...
}

(Older answers for Swift 3 and earlier:)

As of Swift 1.2, String.Index has an initializer

init?(_ utf16Index: UTF16Index, within characters: String)

which can be used to convert NSRange to Range<String.Index> correctly (including all cases of Emojis, Regional Indicators or other extended grapheme clusters) without intermediate conversion to an NSString:

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        let from16 = advance(utf16.startIndex, nsRange.location, utf16.endIndex)
        let to16 = advance(from16, nsRange.length, utf16.endIndex)
        if let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

This method returns an optional string range because not all NSRanges are valid for a given Swift string.

The UITextFieldDelegate delegate method can then be written as

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

    if let swRange = textField.text.rangeFromNSRange(range) {
        let newString = textField.text.stringByReplacingCharactersInRange(swRange, withString: string)
        // ...
    }
    return true
}

The inverse conversion is

extension String {
    func NSRangeFromRange(range : Range<String.Index>) -> NSRange {
        let utf16view = self.utf16
        let from = String.UTF16View.Index(range.startIndex, within: utf16view) 
        let to = String.UTF16View.Index(range.endIndex, within: utf16view)
        return NSMakeRange(from - utf16view.startIndex, to - from)
    }
}

A simple test:

let str = "aπŸ‘ΏbπŸ‡©πŸ‡ͺc"
let r1 = str.rangeOfString("πŸ‡©πŸ‡ͺ")!

// String range to NSRange:
let n1 = str.NSRangeFromRange(r1)
println((str as NSString).substringWithRange(n1)) // πŸ‡©πŸ‡ͺ

// NSRange back to String range:
let r2 = str.rangeFromNSRange(n1)!
println(str.substringWithRange(r2)) // πŸ‡©πŸ‡ͺ

Update for Swift 2:

The Swift 2 version of rangeFromNSRange() was already given by Serhii Yakovenko in this answer, I am including it here for completeness:

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
        let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
        if let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

The Swift 2 version of NSRangeFromRange() is

extension String {
    func NSRangeFromRange(range : Range<String.Index>) -> NSRange {
        let utf16view = self.utf16
        let from = String.UTF16View.Index(range.startIndex, within: utf16view)
        let to = String.UTF16View.Index(range.endIndex, within: utf16view)
        return NSMakeRange(utf16view.startIndex.distanceTo(from), from.distanceTo(to))
    }
}

Update for Swift 3 (Xcode 8):

extension String {
    func nsRange(from range: Range<String.Index>) -> NSRange {
        let from = range.lowerBound.samePosition(in: utf16)
        let to = range.upperBound.samePosition(in: utf16)
        return NSRange(location: utf16.distance(from: utf16.startIndex, to: from),
                       length: utf16.distance(from: from, to: to))
    }
}

extension String {
    func range(from nsRange: NSRange) -> Range<String.Index>? {
        guard
            let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
            let to16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location + nsRange.length, limitedBy: utf16.endIndex),
            let from = from16.samePosition(in: self),
            let to = to16.samePosition(in: self)
            else { return nil }
        return from ..< to
    }
}

Example:

let str = "aπŸ‘ΏbπŸ‡©πŸ‡ͺc"
let r1 = str.range(of: "πŸ‡©πŸ‡ͺ")!

// String range to NSRange:
let n1 = str.nsRange(from: r1)
print((str as NSString).substring(with: n1)) // πŸ‡©πŸ‡ͺ

// NSRange back to String range:
let r2 = str.range(from: n1)!
print(str.substring(with: r2)) // πŸ‡©πŸ‡ͺ
21
votes

This answer by Martin R seems to be correct because it accounts for Unicode.

However at the time of the post (Swift 1) his code doesn't compile in Swift 2.0 (Xcode 7), because they removed advance() function. Updated version is below:

Swift 2

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
        let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
        if let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

Swift 3

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        if let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
            let to16 = utf16.index(from16, offsetBy: nsRange.length, limitedBy: utf16.endIndex),
            let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

Swift 4

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        return Range(nsRange, in: self)
    }
}
19
votes

You need to use Range<String.Index> instead of the classic NSRange. The way I do it (maybe there is a better way) is by taking the string's String.Index a moving it with advance.

I don't know what range you are trying to replace, but let's pretend you want to replace the first 2 characters.

var start = textField.text.startIndex // Start at the string's start index
var end = advance(textField.text.startIndex, 2) // Take start index and advance 2 characters forward
var range: Range<String.Index> = Range<String.Index>(start: start,end: end)

textField.text.stringByReplacingCharactersInRange(range, withString: string)
7
votes

This is similar to Emilie's answer however since you asked specifically how to convert the NSRange to Range<String.Index> you would do something like this:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

     let start = advance(textField.text.startIndex, range.location) 
     let end = advance(start, range.length) 
     let swiftRange = Range<String.Index>(start: start, end: end) 
     ...

}
6
votes

A riff on the great answer by @Emilie, not a replacement/competing answer.
(Xcode6-Beta5)

var original    = "πŸ‡ͺπŸ‡ΈπŸ˜‚This is a test"
var replacement = "!"

var startIndex = advance(original.startIndex, 1) // Start at the second character
var endIndex   = advance(startIndex, 2) // point ahead two characters
var range      = Range(start:startIndex, end:endIndex)
var final = original.stringByReplacingCharactersInRange(range, withString:replacement)

println("start index: \(startIndex)")
println("end index:   \(endIndex)")
println("range:       \(range)")
println("original:    \(original)")
println("final:       \(final)")

Output:

start index: 4
end index:   7
range:       4..<7
original:    πŸ‡ͺπŸ‡ΈπŸ˜‚This is a test
final:       πŸ‡ͺπŸ‡Έ!his is a test

Notice the indexes account for multiple code units. The flag (REGIONAL INDICATOR SYMBOL LETTERS ES) is 8 bytes and the (FACE WITH TEARS OF JOY) is 4 bytes. (In this particular case it turns out that the number of bytes is the same for UTF-8, UTF-16 and UTF-32 representations.)

Wrapping it in a func:

func replaceString(#string:String, #with:String, #start:Int, #length:Int) ->String {
    var startIndex = advance(original.startIndex, start) // Start at the second character
    var endIndex   = advance(startIndex, length) // point ahead two characters
    var range      = Range(start:startIndex, end:endIndex)
    var final = original.stringByReplacingCharactersInRange(range, withString: replacement)
    return final
}

var newString = replaceString(string:original, with:replacement, start:1, length:2)
println("newString:\(newString)")

Output:

newString: !his is a test
4
votes
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

       let strString = ((textField.text)! as NSString).stringByReplacingCharactersInRange(range, withString: string)

 }
2
votes

In Swift 2.0 assuming func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {:

var oldString = textfield.text!
let newRange = oldString.startIndex.advancedBy(range.location)..<oldString.startIndex.advancedBy(range.location + range.length)
let newString = oldString.stringByReplacingCharactersInRange(newRange, withString: string)
1
votes

Here's my best effort. But this cannot check or detect wrong input argument.

extension String {
    /// :r: Must correctly select proper UTF-16 code-unit range. Wrong range will produce wrong result.
    public func convertRangeFromNSRange(r:NSRange) -> Range<String.Index> {
        let a   =   (self as NSString).substringToIndex(r.location)
        let b   =   (self as NSString).substringWithRange(r)

        let n1  =   distance(a.startIndex, a.endIndex)
        let n2  =   distance(b.startIndex, b.endIndex)

        let i1  =   advance(startIndex, n1)
        let i2  =   advance(i1, n2)

        return  Range<String.Index>(start: i1, end: i2)
    }
}

let s   =   "πŸ‡ͺπŸ‡ΈπŸ˜‚"
println(s[s.convertRangeFromNSRange(NSRange(location: 4, length: 2))])      //  Proper range. Produces correct result.
println(s[s.convertRangeFromNSRange(NSRange(location: 0, length: 4))])      //  Proper range. Produces correct result.
println(s[s.convertRangeFromNSRange(NSRange(location: 0, length: 2))])      //  Improper range. Produces wrong result.
println(s[s.convertRangeFromNSRange(NSRange(location: 0, length: 1))])      //  Improper range. Produces wrong result.

Result.

πŸ˜‚
πŸ‡ͺπŸ‡Έ
πŸ‡ͺπŸ‡Έ
πŸ‡ͺπŸ‡Έ

Details

NSRange from NSString counts UTF-16 code-units. And Range<String.Index> from Swift String is an opaque relative type which provides only equality and navigation operations. This is intentionally hidden design.

Though the Range<String.Index> seem to be mapped to UTF-16 code-unit offset, that is just an implementation detail, and I couldn't find any mention about any guarantee. That means the implementation details can be changed at any time. Internal representation of Swift String is not pretty defined, and I cannot rely on it.

NSRange values can be directly mapped to String.UTF16View indexes. But there's no method to convert it into String.Index.

Swift String.Index is index to iterate Swift Character which is an Unicode grapheme cluster. Then, you must provide proper NSRange which selects correct grapheme clusters. If you provide wrong range like the above example, it will produce wrong result because proper grapheme cluster range couldn't be figured out.

If there's a guarantee that the String.Index is UTF-16 code-unit offset, then problem becomes simple. But it is unlikely to happen.

Inverse conversion

Anyway the inverse conversion can be done precisely.

extension String {
    /// O(1) if `self` is optimised to use UTF-16.
    /// O(n) otherwise.
    public func convertRangeToNSRange(r:Range<String.Index>) -> NSRange {
        let a   =   substringToIndex(r.startIndex)
        let b   =   substringWithRange(r)

        return  NSRange(location: a.utf16Count, length: b.utf16Count)
    }
}
println(convertRangeToNSRange(s.startIndex..<s.endIndex))
println(convertRangeToNSRange(s.startIndex.successor()..<s.endIndex))

Result.

(0,6)
(4,2)
1
votes

I've found the cleanest swift2 only solution is to create a category on NSRange:

extension NSRange {
    func stringRangeForText(string: String) -> Range<String.Index> {
        let start = string.startIndex.advancedBy(self.location)
        let end = start.advancedBy(self.length)
        return Range<String.Index>(start: start, end: end)
    }
}

And then call it from for text field delegate function:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let range = range.stringRangeForText(textField.text)
    let output = textField.text.stringByReplacingCharactersInRange(range, withString: string)

    // your code goes here....

    return true
}
1
votes
extension StringProtocol where Index == String.Index {

    func nsRange(of string: String) -> NSRange? {
        guard let range = self.range(of: string) else {  return nil }
        return NSRange(range, in: self)
    }
}
1
votes
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    
    guard let current = textField.text, let r = Range(range, in: current) else {
        return false
    }
    
    let text = current.replacingCharacters(in: r, with: string)
    // ...
    return true
}
0
votes

The Swift 3.0 beta official documentation has provided its standard solution for this situation under the title String.UTF16View in section UTF16View Elements Match NSString Characters title

0
votes

In the accepted answer I find the optionals cumbersome. This works with Swift 3 and seems to have no problem with emojis.

func textField(_ textField: UITextField, 
      shouldChangeCharactersIn range: NSRange, 
      replacementString string: String) -> Bool {

  guard let value = textField.text else {return false} // there may be a reason for returning true in this case but I can't think of it
  // now value is a String, not an optional String

  let valueAfterChange = (value as NSString).replacingCharacters(in: range, with: string)
  // valueAfterChange is a String, not an optional String

  // now do whatever processing is required

  return true  // or false, as required
}
0
votes

Swift 5 Solution

Short answer with main extension

extension NSRange {

    public init(range: Range<String.Index>, 
                originalText: String) {

        self.init(location: range.lowerBound.utf16Offset(in: originalText),
                  length: range.upperBound.utf16Offset(in: originalText) - range.lowerBound.utf16Offset(in: originalText))
    }
}

For detailed answer check here